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H(2)Se has higher boiling point than H(2...

`H_(2)Se` has higher boiling point than `H_(2)S`. This is best explained by

A

Higher extent of hydrogen bonding in `H_(2)Se`

B

Higher polarity of `H_(2)S`

C

Higher polarity of `H_(2)Se`

D

Higher dispersion forces in `H_(2)Se` due to its higher molecular weight.

Text Solution

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The correct Answer is:
D
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Assertion :D_(2)O has higher boiling point than H_(2)O . Reason : Viscosity of H_(2)O(l) is less than that of D_(2)O(l) .

Knowledge Check

  • H_(2)O has higher boiling point than H_(2)S because

    A
    `H_(2)S` is a smaller molecule and hence more closely packed
    B
    the bond angle of `H_(2)O` is more than `H_(2)S` and hence `H_(2)O` molecule are more tightly packet
    C
    the intermolecular hydrogen bonding in liquid `H_(2)O`
    D
    the latent head of voparisation is higher for `H_(2)O` than for `H_(2)S`

  • H_(2)O has a higher boiling point than that of H_(2)O due to

    A
    `H_(2)S` molecular weight is more than `H_(2)O`
    B
    Dispersion forces between water molecules are higher than `H_(2)S`
    C
    Strong ionic bonds between water molecules
    D
    Hydrogen bonds between water molecules

  • NH_(3) has higher boiling point than expected because

    A
    It froms `NH_(4)OH ` with water
    B
    It has intramolecular hydrogen bonds
    C
    It has intramolecular hydrogen bonds
    D
    Its density decreases bond on freezing

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    Asseration: O_(3) has higher boiling point than O_(2) . Reason: O_(3) is allotrope of oxygen

    Statement-1: H_(2)O_(2) is more polar than H_(2)O Statement-2: D_(2)O has higher boiling point than H_(2)O Statement-3: H_(2) bond bond energy is less than D_(2) .

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