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A diatomic molecule has a dipole moment ...

A diatomic molecule has a dipole moment of 1.2 D. If its bond length is equal to `10^(-10)` m then the fraction of an electronic charge on each atom will be

A

`45%`

B

`55%`

C

`75%`

D

`25%`

Text Solution

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The correct Answer is:
To solve the problem, we need to calculate the fraction of an electronic charge on each atom of a diatomic molecule given its dipole moment and bond length. ### Step-by-Step Solution: 1. **Understand the Dipole Moment Formula**: The dipole moment (μ) of a diatomic molecule is given by the formula: \[ \mu = q \cdot d \] where \( q \) is the charge on each atom, and \( d \) is the bond length. 2. **Convert Dipole Moment from Debye to ESU**: The dipole moment is given as 1.2 D (Debye). We need to convert this to electrostatic units (ESU): \[ 1 \text{ D} = 3.33 \times 10^{-10} \text{ ESU cm} \] Therefore, \[ 1.2 \text{ D} = 1.2 \times 3.33 \times 10^{-10} \text{ ESU cm} = 4.0 \times 10^{-10} \text{ ESU cm} \] 3. **Convert Bond Length to Centimeters**: The bond length is given as \( 10^{-10} \) m. We need to convert this to centimeters: \[ 10^{-10} \text{ m} = 10^{-10} \times 100 \text{ cm} = 10^{-8} \text{ cm} \] 4. **Substitute Values into the Dipole Moment Formula**: Now we can substitute the values into the dipole moment formula: \[ 4.0 \times 10^{-10} = q \cdot 10^{-8} \] 5. **Solve for Charge (q)**: Rearranging the equation to solve for \( q \): \[ q = \frac{4.0 \times 10^{-10}}{10^{-8}} = 4.0 \times 10^{-2} \text{ ESU} \] 6. **Convert Charge from ESU to Coulombs**: We know that: \[ 1 \text{ ESU} = 3.33 \times 10^{-10} \text{ C} \] Therefore, converting \( q \) to coulombs: \[ q = 4.0 \times 10^{-2} \text{ ESU} \times 3.33 \times 10^{-10} \text{ C/ESU} = 1.33 \times 10^{-11} \text{ C} \] 7. **Find the Fraction of Electronic Charge**: The charge of an electron is approximately \( 1.6 \times 10^{-19} \text{ C} \). To find the fraction of the electronic charge on each atom: \[ \text{Fraction} = \frac{q}{\text{Charge of an electron}} = \frac{1.33 \times 10^{-11}}{1.6 \times 10^{-19}} = 0.083125 \] 8. **Convert Fraction to Percentage**: To express this fraction as a percentage: \[ \text{Percentage} = 0.083125 \times 100 = 8.3125\% \] 9. **Final Answer**: The fraction of the electronic charge on each atom is approximately \( 8.31\% \).
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Knowledge Check

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