Home
Class 12
PHYSICS
An iron bar of length 10 m is heated fro...

An iron bar of length 10 m is heated from `0^@C " to " 100^@C`. If the coefficient of linear thermal expansion of iron is `10xx10^(-6) .^@C^(-1)` , then increase in the length of bar (in cm ) is

A

0.5 cm

B

1.0 cm

C

1.5 cm

D

2.0 cm

Text Solution

AI Generated Solution

The correct Answer is:
To find the increase in length of the iron bar when heated, we can use the formula for linear thermal expansion: \[ \Delta L = \alpha \cdot L_0 \cdot \Delta T \] Where: - \(\Delta L\) = change in length - \(\alpha\) = coefficient of linear thermal expansion - \(L_0\) = original length of the bar - \(\Delta T\) = change in temperature ### Step 1: Identify the given values - Original length of the bar, \(L_0 = 10 \, \text{m}\) - Coefficient of linear thermal expansion, \(\alpha = 10 \times 10^{-6} \, \text{°C}^{-1}\) - Initial temperature, \(T_i = 0 \, \text{°C}\) - Final temperature, \(T_f = 100 \, \text{°C}\) ### Step 2: Calculate the change in temperature \[ \Delta T = T_f - T_i = 100 \, \text{°C} - 0 \, \text{°C} = 100 \, \text{°C} \] ### Step 3: Substitute the values into the formula \[ \Delta L = (10 \times 10^{-6}) \cdot (10) \cdot (100) \] ### Step 4: Perform the calculations \[ \Delta L = 10 \times 10^{-6} \cdot 10 \cdot 100 = 10 \times 10^{-6} \cdot 1000 = 10 \times 10^{-3} \, \text{m} \] ### Step 5: Convert meters to centimeters Since \(1 \, \text{m} = 100 \, \text{cm}\): \[ \Delta L = 10 \times 10^{-3} \, \text{m} = 10 \, \text{cm} \] ### Final Answer The increase in the length of the iron bar is \(1 \, \text{cm}\). ---
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • NTA NEET SET 41

    NTA MOCK TESTS|Exercise PHYSICS|45 Videos
  • NTA NEET SET 43

    NTA MOCK TESTS|Exercise PHYSICS|45 Videos

Similar Questions

Explore conceptually related problems

An iron bar of length 10 m is heated from 0^@C to 100^@C . If the coefficient of linear thermal expansion of iron is 10xx10^(-6)//@_C , the increase in the length of bat is :

An iron bar of length 10 m is heated from 0^@C to 100^@C . If the coefficient of linear thermal expansion of iron is 10xx10^(-6)//@_C , the increase in the length of bat is :

Knowledge Check

  • An iron bar 10 cm in length is kept at 20^@C . If the coefficient of linear expansion of iron is alpha = 11 xx 10^(-6).^(@)C^(-1) , then at 19^(@)C it will be

    A
    `11 xx 10^(-6)cm` longer
    B
    `11 xx 10^(-6)cm` shorter
    C
    `11 xx 10^(-5)cm` shorter
    D
    `11 xx 10^(-5)cm` longer
  • A metallic bar is heated from 0^(@)C to 100^(@)C . The coefficient of linear expansion is 10^(-5)K^(-1) . What will be the percentage increase in length

    A
    `0.01%`
    B
    `0.1%`
    C
    `1%`
    D
    `10%`
  • The coefficient of linear expansion of a metal rod is 12 xx 10^(-6//0)C , its value in per ^(0)F

    A
    `(20)/(3) xx 10^(-6//0)F`
    B
    `(15)/(4) xx 10^(-6//0)F`
    C
    `21.6 xx 10^(-6//0)F`
    D
    `12 xx 10^(-6//0)F`
  • Similar Questions

    Explore conceptually related problems

    A metal cube of length of 10.0 mm at 0^(@)C is heated to 200^(@)C . Given: its coefficient of linear expansion is 2xx10^(-5)K^(-1) . The percent change of its volume is

    An aluminium measuring rod, which is correct at 5^@C measures the length of a line as 80 cm at 45^@C If thermal coefficient of linear expansion of aluminium is 2.50xx10^(-4)//^@C , the correct length of the line is:

    The length of a brass rod is 1.5 m. Its coefficient of linear expansion is 19xx10^(-6)K^(-1) Find the increase in length of the rod if it is heated through 20^(@)C .

    The ends Q and R of two thin wires, PQ and RS, are soldered (joined) together. Initially each of the of wire has a length of 1m at 10^@C. Now the end P is maintained at 10^@C, while the ends S is heated and maintained at 400^@C. The system is thermally insultated from its surroundings. If the thermal conductivity of wire PQ is twice that of the wire RS and the coefficient of linear thermal expansion of PQ is 1.2xx10^-5K^-1, the change in length of the wire PQ is

    The ratio of densites or iron at 10^@C is (alpha of iron = 10xx10^(-6), .^@C^(-1))