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Time periods of vibration of two bar mag...

Time periods of vibration of two bar magnets in sum and difference positions are 4 s and 6 s respectively . The ratio of their magnetic moments `(M_1)/(M_2)` is

A

`6:4`

B

`36 : 16`

C

`2.6:1`

D

`1.5:1`

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The correct Answer is:
To solve the problem, we need to find the ratio of the magnetic moments \( \frac{M_1}{M_2} \) of two bar magnets based on their time periods of vibration in sum and difference positions. The time periods are given as follows: - Time period in sum position \( T_1 = 4 \, \text{s} \) - Time period in difference position \( T_2 = 6 \, \text{s} \) ### Step-by-Step Solution: 1. **Identify the Formula**: The ratio of the magnetic moments \( \frac{M_1}{M_2} \) can be calculated using the formula: \[ \frac{M_1}{M_2} = \frac{T_2^2 + T_1^2}{T_2^2 - T_1^2} \] 2. **Substitute the Values**: Substitute \( T_1 \) and \( T_2 \) into the formula: \[ \frac{M_1}{M_2} = \frac{6^2 + 4^2}{6^2 - 4^2} \] 3. **Calculate \( T_1^2 \) and \( T_2^2 \)**: - Calculate \( T_1^2 = 4^2 = 16 \) - Calculate \( T_2^2 = 6^2 = 36 \) 4. **Plug in the Squared Values**: Now substitute these squared values back into the equation: \[ \frac{M_1}{M_2} = \frac{36 + 16}{36 - 16} \] 5. **Simplify the Numerator and Denominator**: - Numerator: \( 36 + 16 = 52 \) - Denominator: \( 36 - 16 = 20 \) 6. **Calculate the Ratio**: Now we can calculate the ratio: \[ \frac{M_1}{M_2} = \frac{52}{20} \] 7. **Simplify the Fraction**: Simplifying \( \frac{52}{20} \): \[ \frac{M_1}{M_2} = 2.6 \] ### Final Answer: Thus, the ratio of their magnetic moments \( \frac{M_1}{M_2} \) is: \[ \frac{M_1}{M_2} = 2.6 : 1 \]
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