An X - ray tube produces a continuous sp...

An X - ray tube produces a continuous spectrum of radiation with its shortest wavelength of `45xx10^(-2)Å`. The maximum energy of a photon in the radiation in eV is `(h = 6.62xx10^(-34)Js, c=3xx10^(8)ms^(-1))`

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An X-ray tube produces a continuous spectrum of radiation with its short wavelength end at 0.42Å. What is the maximum energy of photon in the radiation? What is the order of accelerating voltage (for electrons) requirement in such a case? h=6.62xx10^(-34)Js and e=1.6xx10^(-19)C

(a) An X-ray tube produces a continuous spectrum of radiation with its shorts wavelength end ate 0.45 Å . What is the maximum energy of the photon in the radiation? (b) From your answer to (a) , guess what order of accelerating voltage (for electrons) is required in such a tube?

The energy of X-ray photon of wavelength 1.65 Å is (h=6.6 xx 10^(-34)J-sec,c=3xx10^(8)ms^(-1),1eV=1.6xx10^(-19)J)

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The frequency of a photon associated with an energy of 3.31eV is ( given h=6.62xx10^(-34) Js )

The photosensitive surface is receiving the light of wavelength 5000Å at the rate of 10^(-8)"J s"^(-1) . The number of photons received per second is (h=6.62xx10^(-34)Js, c=3xx10^(8)ms^(-1))

Calculate the frequency of a photon, having energy 41.25 eV. (h=6.6xx10^(-34) Js) .

NTA MOCK TESTS-NTA NEET SET 58-PHYSICS

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