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An object is placed at a distance of 20 ...

An object is placed at a distance of 20 cm from the pole of a concave mirror of focal length 10 cm. The distance of the image formed is

A

`+20 cm`

B

`+10Cm`

C

`-20 cm`

D

`-10cm`

Text Solution

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The correct Answer is:
To solve the problem of finding the distance of the image formed by a concave mirror, we will use the mirror formula: \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \] Where: - \( f \) = focal length of the mirror - \( v \) = image distance from the mirror - \( u \) = object distance from the mirror ### Step 1: Identify the given values - The object distance \( u = -20 \) cm (negative because the object is in front of the mirror). - The focal length \( f = -10 \) cm (negative for concave mirrors). ### Step 2: Substitute the values into the mirror formula Using the mirror formula: \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \] Substituting the known values: \[ \frac{1}{-10} = \frac{1}{v} + \frac{1}{-20} \] ### Step 3: Rearranging the equation Rearranging the equation gives: \[ \frac{1}{v} = \frac{1}{-10} + \frac{1}{20} \] ### Step 4: Finding a common denominator The common denominator for -10 and 20 is 20. Thus, we rewrite the fractions: \[ \frac{1}{v} = \frac{-2}{20} + \frac{1}{20} \] ### Step 5: Simplifying the equation Now, combine the fractions: \[ \frac{1}{v} = \frac{-2 + 1}{20} = \frac{-1}{20} \] ### Step 6: Solve for \( v \) Taking the reciprocal gives: \[ v = -20 \text{ cm} \] ### Conclusion The distance of the image formed is \( -20 \) cm, which indicates that the image is formed on the same side as the object.
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