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Two deuterium nuclei each of mass m fuse, together to form a Helium nucleus, releasing and energy E. If c is the velocity of light, the mass of Helium nucleus formed will be

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A deuterium reaction that occurs in an experimental fusion reactor is in two stage: (a) Two deuterium (._1^2D) nuclei fuse together to form a tritium nucleus, with a proton as a by product written as D(D,p)T . (b) A tritium nucleus fuses with another deuterium nucleus to form a helium ._2^4He nucleus with neutron as a by - product, written as T (D,n) ._2^4He . Compute (a) the energy released in each of the two stages, (b) the energy released in the combined reaction per deutrium. (c ) What percentage of the mass energy of the initial deuterium is released. Given, {:(._1^2D=2.014102 am u),(._1^3 T=3.016049), (._2^4 He =4.002603 am u),(._1^1 H =1.007825 am u),(._0^1 n =1.00665 am u):} .

four nuclei of an element fuse together to form a heavier nucleus. If the process is accompanied by release of energy, which of the two -the parent or the daughter nucleus would have higher binding energy per nucleon?

Knowledge Check

  • When two deuterium nuclei fuse together to form a tritium nuclei, we get a

    A
    Neutron
    B
    Deuteron
    C
    `alpha-`particle
    D
    Proton
  • When two nuclei (A le 10) fuse together to form a heavier nucleus, the

    A
    binding energy per uncleon increases.
    B
    binding energy per uncleon decreases.
    C
    binding energy per nucleon does not change.
    D
    total binding energy decreases.
  • Two deutrons each of mass m fuse to form helium resulting in release of energy E. The mass of helium formed is

    A
    `m+E//c^(2)`
    B
    `2m+E//c^(2)`
    C
    `E//mc^(2)`
    D
    `2m-E//c^(2)`
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