Two deuterium nuclei each of mass m fuse, together to form a Helium nucleus, releasing and energy E. If c is the velocity of light, the mass of Helium nucleus formed will be

When two deuterium nuclei fuse together to form a tritium nuclei, we get a

Two deutrons each of mass m fuse to form helium resulting in release of energy E. The mass of helium formed is

Two small nuclei of mass m fuse together to form a resulting nucleus P The mass of nucleus P is (the energy released is E)

If the nuclei of masess X and Y are fused together to form a nucleus of mass m and some energy is released, then

If two nuclei of mass number A_(1) and A_(2) fuse together to form a nucleus of mass number A, then

A deuterium reaction that occurs in an experimental fusion reactor is in two stage: (a) Two deuterium (._1^2D) nuclei fuse together to form a tritium nucleus, with a proton as a by product written as D(D,p)T . (b) A tritium nucleus fuses with another deuterium nucleus to form a helium ._2^4He nucleus with neutron as a by - product, written as T (D,n) ._2^4He . Compute (a) the energy released in each of the two stages, (b) the energy released in the combined reaction per deutrium. (c ) What percentage of the mass energy of the initial deuterium is released. Given, {:(._1^2D=2.014102 am u),(._1^3 T=3.016049), (._2^4 He =4.002603 am u),(._1^1 H =1.007825 am u),(._0^1 n =1.00665 am u):} .