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The abscissae of the two points A and B ...

The abscissae of the two points A and B are the roots of the equation `x^(2) + 2ax-b^(2) =0` and their ordinates are the roots of the equation `x^(2)+2px-q^(2)=0`. Find the equation and the radius of the circle with `bar(AB)` as diameter.

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The abscissa of the two points A and B are the roots of the equation x^(2)+2ax-b^(2)=0 and their ordinates are the roots of the equation x^(2)+2px-q^(2)=0. Find the equation of the circle with AB as diameter.Also,find its radius.

The abscissa of two points A and B are the roots of the equation x^(2)+2ax-b^(2)=0 and ordinates are the roots of equation x^(2)+2ax-b^(2)=0 . Find the equation of the circle whose diameter is AB.

Knowledge Check

  • The abscisae of A and B are the roots of the equation x ^(2) + 2ax -b ^(2) =0 and their ordinates are the roots of the equation y ^(2) + 2 py -q ^(2) =0. The equation of the circle with AB as diameter is

    A
    `x ^(2) + y^(2) + 2ax + 2py-b ^(2) -q ^(2) =0`
    B
    `x ^(2) + y^(2) + 2ax+ 2py -b ^(2) -q ^(2) =0`
    C
    `x ^(2) + y^(2) + 2ax + 2py + b^(2) + q^(2) =0`
    D
    None of these
  • If p, q are the roots of the equation x^(2)+px +q=0 , then

    A
    p = 1, q = -2
    B
    p = 0, q = 1
    C
    p = -2, q = 0
    D
    p = -2, q = 1
  • If p and q are the roots of the equation x^2+px+q=0 , then :

    A
    p = 1 or 0
    B
    p = -2 or 0
    C
    p = -2
    D
    p = 1
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    The abscissa of two points A and B are the roots of the equation x^(2)+2ax-b^(2)=0 and their ordinates are the roots of y^(2)+2py-q^(2)=0 then the distance AB in terms of a,b,p,q is

    The abscissae of two points A and B are the roots of the equaiton x^2 + 2x-a^2 =0 and the ordinats are the roots of the equaiton y^2 + 4y-b^2 =0 . Find the equation of the circle with AB as its diameter. Also find the coordinates of the centre and the length of the radius of the circle.

    The abscissae of two points Aand B are the roots of the equation x^(2)+2ax-b^(2)=0 and their ordinates are the roots of y^(2)+2py-q^(2)=0 then the distance AB in terms of a,b,p,q is

    A abscissa of A and B are the roots of the equation x^2+2ax-b^2=0 and their ordinates are roots of the equation y^2+2py-q^2=0 . The equation of the circle with AB as diameter is

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