The set of principal (n), azimuthal (l) ...

The set of principal (n), azimuthal (l) and magnetic `(m_(l))` quantum number that is not allowed for the electron in H-atom is

n = 3, l = 1, `m_(l) = -1`

n = 3, l = 0, `m_(l) = 0`

n = 2, l = 1, `m_(l)= 0`

n = 2, l = 2, `m_(l) = -1`

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The correct Answer is:

n is always greater than l
and m = - l……….0 ………..+l
If n = 2, then l = 0, 1
and `m_(l) = 0, { -1, 0, + 1}`

An electron in an atom can be completely designated with the help of four quantum numbers. Out of these, the first three i.e., principal (n), azimuthal (l) and magnetic (m) quantum number are obtained from the solution of Shrodinger wave equation while the spin(s) quantum number arises from the spin of the electron around its axis clockwise or antiaclockwise. Ot of these principal quantum number tells about the size, azimuthal quantum number about the shape and magnetic quantum signifies the orientation of the electron orbital. How many electrons in a given atom have the following set of quantium numbers? n = 3, l =2, m = +2, s = -1//2

cannot be known

`1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(3)`

`1s^(2) 2s^(2) 2p^(6) 3s^(2)`

`1s^(2)2s^(2) 2p^(6)`

`1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(1)`

`l+2`

`2l+1`

`l(l+1)`

`sqrt(l(l+1))`