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The amount (in mol) of bromoform (CHBr(3...

The amount (in mol) of bromoform `(CHBr_(3))` produced when 1.0 mol of acetone reacts completely with 1.0 mol of bromine in the presence of aqueous NaOH is

A

`1/3`

B

`2/3`

C

`1`

D

`2`

Text Solution

Verified by Experts

The correct Answer is:
A
`underset( 1 "mole")(CH_(3)-overset(O) overset(||)C-CH_(3))+3Br^(2)+underset(1 "mole")(4NaOH)toCH_(3)-overset(O)overset(||)C-overset(-)(O)Na^(+)+3NaBr+3H_(2)O+underset(1//3 " mol" )(CHBr_(3))`
Moles of bromoform produced `=1//3` mole
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Knowledge Check

  • Acetylene on reaction with 1 mol of HCl in the presence of mercuric chloride produces

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