Answer
Step by step text solution for If z is complex number, then the locus of z satisfying the condition |2z-1|=|z-1| is (a)perpendicular bisector of line segment joining 1/2 and 1 (b)circle (c)parabola (d)none of the above curves by MATHS experts to help you in doubts & scoring excellent marks in Class 11 exams.
|
Similar Questions
Explore conceptually related problems
Recommended Questions
- If z is complex number, then the locus of z satisfying the condition...
01:17
|
Playing Now - If the complex number z=x+i y satisfies the condition |z+1|=1, then ...
02:04
|
Play - If z is complex number, then the locus of z satisfying the condition...
01:17
|
Play - The locus of the complex number z satisfying the inequaliyt log(1/sqrt...
05:19
|
Play - If Re((2z+1)/(iz+1))=1, the the locus of the point representing z in t...
04:41
|
Play - |z-4|+|z+4|=16 where z is as complex number ,then locus of z is (A) a ...
03:39
|
Play - Statement-1: If z is a complex number satisfying (z-1)^(n)=z^n , n in ...
03:28
|
Play - If a complex number z satisfies |z|^(2)+1=|z^(2)-1|, then the locus of...
06:19
|
Play - The locus of a complex number z satisfying |z-(1+3i)|+|z+3-6i|=4 (A)...
06:47
|
Play