The asymptotes of a hyperbola are `y = pm b/a x`, prove that the equation of the hyperbola is `x^(2)/a^(2) - y^(2)/b^(2) = k ` , where k is any constant.

The asymptotes of the hyperbola xy–3x–2y=0 are

Equation of conjugate hyperbola w.r.t (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 is

Asymptotes of the hyperbola xy=4x+3y are

The auxiliary equation of circle of hyperbola (x ^(2))/(a ^(2)) - (y^(2))/(b ^(2)) =1, is

The angle between the asymptotes of the hyperbola (x^2)/(a^2)-(y^2)/(b^2)=1 is

Statement -1 : The lines y = pm b/a xx are known as the asymptotes of the hyperbola x^(2)/a^(2) - y^(2)/b^(2) - 1 = 0 . because Statement -2 : Asymptotes touch the curye at any real point .

The angle between the asymptotes of the hyperbola 3x^(2)-y^(2)=3 , is

The equation of the asymptotes of a hyperbola are 4x+3y+2=0 and 3x-4y+1=0 then equations of axes arex