If vecr.veca=vecr.vecb=vecr.vecc=0 " where "veca,vecb and vecc are non-coplanar, then
Solve veca.vecr=x, vecb.vecr=y, vecc.vecr=z , where veca,vecb,vecc are given non coplanar vectors.
Find vector vecr if vecr.veca=m and vecrxxvecb=vecc, where veca.vecb!=0
Statement 1: Any vector in space can be uniquely written as the linear combination of three non-coplanar vectors. Stetement 2: If veca, vecb, vecc are three non-coplanar vectors and vecr is any vector in space then [(veca,vecb, vecc)]vecc+[(vecb, vecc, vecr)]veca+[(vecc, veca, vecr)]vecb=[(veca, vecb, vecc)]vecr
If vecr.veca=vecr.vecb=vecr.vecc=0 for some non-zero vectro vecr , then the value of [(veca, vecb, vecc)] is
If vecP = (vecbxxvecc)/([vecavecbvecc]).vecq=(veccxxveca)/([veca vecb vecc])and vecr = (vecaxxvecb)/([veca vecbvecc]), " where " veca,vecb and vecc are three non- coplanar vectors then the value of the expression (veca + vecb + vecc ). (vecq+ vecq+vecr) is
Let vecr be a non - zero vector satisfying vecr.veca = vecr.vecb =vecr.vecc =0 for given non- zero vectors veca vecb and vecc Statement 1: [ veca - vecb vecb - vecc vecc- veca] =0 Statement 2: [veca vecb vecc] =0
If vecp=(vecbxxvecc)/([(veca,vecb,vecc)]),vecq=(veccxxveca)/([(veca,vecb,vecc)]),vecr=(vecaxxvecb)/([(veca,vecb,vecb)]) where veca,vecb,vecc are three non-coplanar vectors, then the value of the expression (veca+vecb+vecc).(vecp+vecq+vecr) is
Assertion: If vecr.veca=0, vecr.vecb=0, vecr.vecc=0 for some non zero vector vecr e then veca,vecb,vecc are coplanar vectors. Reason : If veca,vecb,vecc are coplanar then veca+vecb+vecc=0 (A) Both A and R are true and R is the correct explanation of A (B) Both A and R are true R is not te correct explanation of A (C) A is true but R is false. (D) A is false but R is true.
