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A ball of mass 1 kg is dropped from 20 m...

A ball of mass 1 kg is dropped from 20 m height on ground and it rebounds to height 5m. Find magnitude of change in momentum during its collision with the ground. (Take `g=10m//s^(2)`)

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Knowledge Check

  • A body of mass 2 kg is dropped from a height of 1 m. It s kinetic as it reaches the ground is

    A
    19.6 J
    B
    19.6 N
    C
    19.6 kg
    D
    19.6 m
  • A ball of mass m falls vertically to the ground from a height h_1 and rebound to a height h_1 and rebound to a height h_2 . The change in momentum of the ball on striking the ground is.

    A
    `mg(h_1 - h_2)`
    B
    `m(sqrt(2 gh_1) + sqrt(2 gh_2))`
    C
    `m sqrt(2g(h_1 + h_2))`
    D
    `m sqrt(2 g)(h_1 + h_2)`
  • A ball of mass 1kg is dropped from a height of h = 5m. It rebounds losing 50% of its total mechanical energy during collision. Then choose the correct statement(s) from the following .

    A
    After collision speed of ball is `5m//s`
    B
    After collision speed of ball is `5 sqrt(2) m//s`
    C
    The value of impulse is `( 10 - 5 sqrt( 2)) Ns`.
    D
    The value of impulse is `( 10 + 5 sqrt(2)) Ns`
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    A body falling on the ground from a height of 10m rebounds to a height of 2.5m . Calculate (i) the percentage loss of kinetic energy of the body during its collision with the ground. (ii) ratio of the velocities of the body just before and just after collision.

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