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The average speed of gas molecules is v ...

The average speed of gas molecules is v at pressure P, If by keeping temperature constant the pressure of gas is doubled, then average speed will become

A

`sqrt(2) V`

B

`v`

C

`2v`

D

`(v)/(sqrt2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze how the average speed of gas molecules changes when the pressure is doubled while keeping the temperature constant. ### Step-by-Step Solution: 1. **Understanding Average Speed of Gas Molecules**: The average speed of gas molecules can be expressed using the formula: \[ v_{avg} = \sqrt{\frac{8RT}{\pi m}} \] where \( R \) is the universal gas constant, \( T \) is the absolute temperature, and \( m \) is the mass of a gas molecule. 2. **Given Conditions**: We are given that the average speed of gas molecules is \( v \) at pressure \( P \) and temperature \( T \). We need to analyze the situation when the pressure is doubled (i.e., \( P' = 2P \)) while keeping the temperature constant. 3. **Using Ideal Gas Law**: According to the ideal gas law: \[ PV = nRT \] If we keep the temperature constant and double the pressure, the volume must decrease to maintain the equation. This means: \[ P'V' = nRT \quad \text{(where \( V' \) is the new volume)} \] Since \( P' = 2P \), we have: \[ 2PV' = nRT \] Thus, the new volume \( V' \) will be: \[ V' = \frac{nRT}{2P} \] This indicates that the volume has decreased. 4. **Effect on Density**: Since density (\( \rho \)) is defined as mass per unit volume, if the volume decreases while the mass remains constant, the density must increase. Therefore, we can conclude: \[ \rho' = \frac{m}{V'} > \rho \] (where \( \rho' \) is the new density). 5. **Revisiting Average Speed**: The average speed formula can also be expressed in terms of pressure and density: \[ v_{avg} = \sqrt{\frac{8R}{\pi} \cdot \frac{P}{\rho}} \] Since we are keeping temperature constant, the term \( \frac{8R}{\pi} \) remains constant. When pressure is doubled, we have: \[ v_{avg}' = \sqrt{\frac{8R}{\pi} \cdot \frac{2P}{\rho'}} \] However, as we have established, increasing pressure leads to an increase in density. The increase in pressure and density will offset each other in the average speed equation. 6. **Conclusion**: Since the average speed depends only on temperature and not on pressure or density, we can conclude that: \[ v_{avg}' = v_{avg} \] Thus, the average speed remains unchanged when the pressure is doubled at constant temperature. ### Final Answer: The average speed will remain \( v \) even if the pressure is doubled.
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Knowledge Check

  • The average speed of gas molecules is equal to

    A
    `((8 RT)/(pi M))^(1//2)`
    B
    `((3 RT)/( M))^(1//2)`
    C
    `((2 RT)/( M))^(1//2)`
    D
    `(( RT)/( M))^(1//2)`
  • The average pressure of an ideal gas is

    A
    `p=(1//3)mnV_(av)^(2)`
    B
    `p=(1//2)mnV_(av)`
    C
    `p=(1//4)mnV_(av)^(2)`
    D
    `p=(1//3)mnV_(av)`
  • By increasing temperature and keeping the volume constant, the pressure of a gas will

    A
    remain constant
    B
    increase
    C
    decrease
    D
    increase or decrease depends on the nature of gas
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