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A chemist was performing an experiment t...

A chemist was performing an experiment to study the effect of varying voltage on the velocity and de Broglie wavelength of the electrons. In first experiment, the electron was accelerated through a potential difference of 1kV and in second experiment, it was accelerated through a potential difference of 2kV.
The wavelength of de Broglie waves associated with electron is given by:
`lamda=(h)/(sqrt(2qVm))`
where, V is the voltage through which an electron is accelerated.
Putting the values of h, m and q we get:
`lamda=(12.3)/(sqrt(V))`Ã…
Q. The velocity of electron will be:

A

same in both

B

1.4 times in second experiment than in first experiment

C

double in second experiment than in first experiment

D

four tiems in the second case than in first case.

Text Solution

Verified by Experts

The correct Answer is:
b
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Knowledge Check

  • A chemist was performing an experiment to study the effect of varying voltage on the velocity and de Broglie wavelength of the electrons. In first experiment, the electron was accelerated through a potential difference of 1kV and in second experiment, it was accelerated through a potential difference of 2kV. The wavelength of de Broglie waves associated with electron is given by: lamda=(h)/(sqrt(2qVm)) where, V is the voltage through which an electron is accelerated. Putting the values of h, m and q we get: lamda=(12.3)/(sqrt(V)) Ã… Q. The wavelength of electron will be:

    A
    1.4 times in first case than in second case
    B
    1.4 times in second case than in first case
    C
    double in second case than in first case
    D
    double in first case than in second case

  • A chemist was performing an experiment to study the effect of varying voltage on the velocity and de Broglie wavelength of the electrons. In first experiment, the electron was accelerated through a potential difference of 1kV and in second experiment, it was accelerated through a potential difference of 2kV. The wavelength of de Broglie waves associated with electron is given by: lamda=(h)/(sqrt(2qVm)) where, V is the voltage through which an electron is accelerated. Putting the values of h, m and q we get: lamda=(12.3)/(sqrt(V)) Ã… Q. In order to get half velocity of electrons in second case, the applied potential will be:

    A
    0.25 kV
    B
    2 kV
    C
    0.5 kV
    D
    0.75 kV

  • A physicist was performing experiments to study the effect of varying voltage on the velocity and wavelength of the electrons. In one case, the electron was accelerated through a potential difference of 1kV and in the second case, it was accelerated through a potential difference of 2kV The wavelength associated with the electron will be

    A
    double in the second case than in the first case
    B
    double in the first case than in the second case
    C
    1.4 times in the second case than in the first case
    D
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