A chemist was performing an experiment to study the effect of varying voltage on the velocity and de Broglie wavelength of the electrons. In first experiment, the electron was accelerated through a potential difference of 1kV and in second experiment, it was accelerated through a potential difference of 2kV.
The wavelength of de Broglie waves associated with electron is given by:
`lamda=(h)/(sqrt(2qVm))`
where, V is the voltage through which an electron is accelerated.
Putting the values of h, m and q we get:
`lamda=(12.3)/(sqrt(V))`Ã…
Q. The velocity of electron will be:

Options

A. same in both
B. 1.4 times in second experiment than in first experiment
C. double in second experiment than in first experiment
D. four tiems in the second case than in first case.

Answer

b