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In which of the following reactions H(2)...

In which of the following reactions `H_(2)O_(2)` acts as reducing agent?
(A) `H_(2)O_(2)+2H^(+)+2e^(-) to 2H_(2)O`
(B) `H_(2)O_(2)-2e^(-) to O_(2)+2H^(+)`
(C ). `H_(2)O_(2)+2e^(-) to 2OH^(-)`
(D) `H_(2)O_(2)+2OH^(-)-2e^(-) to O_(2)+2H_(2)O`

A

A,C

B

B,D

C

A,B

D

C,D

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The correct Answer is:
To determine in which of the given reactions \( H_2O_2 \) acts as a reducing agent, we need to analyze each reaction and identify the oxidation states of the elements involved, particularly focusing on the oxidation state of oxygen in \( H_2O_2 \). ### Step-by-Step Solution: 1. **Understanding Reducing Agents**: A reducing agent is a substance that donates electrons in a chemical reaction and is oxidized in the process. This means that the reducing agent itself undergoes an increase in oxidation state. 2. **Analyzing Each Reaction**: We will analyze the oxidation states of oxygen in \( H_2O_2 \) for each reaction. **(A)** \( H_2O_2 + 2H^+ + 2e^- \rightarrow 2H_2O \) - In \( H_2O_2 \), oxygen is in the -1 oxidation state. - In \( H_2O \), oxygen is in the -2 oxidation state. - Since oxygen goes from -1 to -2, \( H_2O_2 \) is reduced, and therefore, it acts as an oxidizing agent. **(B)** \( H_2O_2 - 2e^- \rightarrow O_2 + 2H^+ \) - In \( H_2O_2 \), oxygen is in the -1 oxidation state. - In \( O_2 \), oxygen is in the 0 oxidation state. - Since oxygen goes from -1 to 0, \( H_2O_2 \) is oxidized, and therefore, it acts as a reducing agent. **(C)** \( H_2O_2 + 2e^- \rightarrow 2OH^- \) - In \( H_2O_2 \), oxygen is in the -1 oxidation state. - In \( OH^- \), oxygen is in the -2 oxidation state. - Since oxygen goes from -1 to -2, \( H_2O_2 \) is reduced, and therefore, it acts as an oxidizing agent. **(D)** \( H_2O_2 + 2OH^- - 2e^- \rightarrow O_2 + 2H_2O \) - In \( H_2O_2 \), oxygen is in the -1 oxidation state. - In \( O_2 \), oxygen is in the 0 oxidation state. - Since oxygen goes from -1 to 0, \( H_2O_2 \) is oxidized, and therefore, it acts as a reducing agent. 3. **Conclusion**: From the analysis, \( H_2O_2 \) acts as a reducing agent in reactions (B) and (D). ### Final Answer: **(B) and (D)** are the reactions in which \( H_2O_2 \) acts as a reducing agent.

To determine in which of the given reactions \( H_2O_2 \) acts as a reducing agent, we need to analyze each reaction and identify the oxidation states of the elements involved, particularly focusing on the oxidation state of oxygen in \( H_2O_2 \). ### Step-by-Step Solution: 1. **Understanding Reducing Agents**: A reducing agent is a substance that donates electrons in a chemical reaction and is oxidized in the process. This means that the reducing agent itself undergoes an increase in oxidation state. 2. **Analyzing Each Reaction**: ...
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