Home
Class 11
CHEMISTRY
A solution contains Na(2)CO(3) " and " N...

A solution contains `Na_(2)CO_(3) " and " NaHCO_(3)`. 10 mL of the solution required 2.5 mL of 0.1 M`H_(2)SO_(4)` for neutralisation using phenolphthalein as indicator. Methyl orange is then added when a further 2.5 mL of `0.2 M H_(2)SO_(4)` was required. Calculate the amount of `Na_(2)CO_(3) " and" NaHCO_(3)` in one litre of the solution.

Text Solution

Verified by Experts

2.5 mL of `0.1 M H_(2)SO_(4)=2.5 mL " of" 0.2 N H_(2)SO_(4)`
`=(1)/(2)Na_(2)CO_(3)` present in 10 mL of mixture
So,
`5 mL " of" 0.2 N H_(2)SO_(4)=Na_(2)CO_(3)` present in 10 mL of mixture
`-=5 mL " of" 0.2 N Na_(2)CO_(3)`
`-=(0.2xx53)/(1000)xx5=0.053 g`
Amount of `Na_(2)CO_(3)=(0.053)/(10)xx1000=5.3 g//L` of mixture
Between first and second end points,
=2.5 mL of `0.2 M H_(2)SO_(4)` used
=2.5 mL of `0.4N H_(2)SO_(4)` used
=5 mL of `0.2 N H_(2)SO_(4)` used
`-=(1)/(2)Na_(2)CO_(3)+NaHCO_(3)` present in 10 mL of mixture
`(5-2.5)mL 0.2 N H_(2)SO_(4)`
`-=NaHCO_(3)` present in 10 mL of mixture
`-=2.5 mL 0.2 N NaHCO_(3)`
`-=(0.2xx84)/(1000)xx2.5=0.042 g`
Amount of `NaHCO_(3)=(0.042)(10)xx1000=4.20 g//L` of mixture.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • VOLUMETRIC ANALYSIS

    OP TANDON|Exercise Example 18|2 Videos
  • VOLUMETRIC ANALYSIS

    OP TANDON|Exercise Example 19|2 Videos
  • VOLUMETRIC ANALYSIS

    OP TANDON|Exercise Example 16|2 Videos
  • THE COLLOIDAL STATE

    OP TANDON|Exercise Self Assessment|21 Videos

Similar Questions

Explore conceptually related problems

A solution contains Na_(2)CO_(3) and NaHCO_(3) . 10 mL of the solution requires 2.5 mL of 0.1 " M " H_(2)SO_(4) for neutralisation using phenlphthalein as an indicator . Methyl orange is added when a further 2.5 mL of 0.2 " M " H_(2)SO_(4) was required . calculate the amount of Na_(2)CO_(3) and NaHCO_(3) in one litre of the solution .

A solution contains Na_(2)CO_(3) and NaHCO_(3) 20 cm^(3) of this solution requires 5.0 cm3 of 0.1 M H_(2) SO_(4) solution for neutralization using phenolphthalein as the indicator. Methylorange is then added when a further 5.0 cm^(3) of 0.2 M H_(2)SO_(4) was required. Calculate the masses of Na_(2)CO_(3) and NaHCO_(3) in 1 L of this solution.

Knowledge Check

  • A solution contains Na_(2)CO_(3) " and " NaHCO_(3) . 10 mL of the solution required 2.5 mL of 0.1 M H_(2)SO_(4) for neutralisation using phenophthalein as indicator. Methyl orange is then added when a further 2.5 mL of 0.2 M H_(2)SO_(4) was required . Then the amount of Na_(2)CO_(3) " and " NaHCO_(3) in 1 litre of the solution is :

    A
    5.3 g and 4.2 g
    B
    3.3 g and 6.2 g
    C
    4.2 g and 5.3 g
    D
    6.2 g and 3.3 g
  • A solution contains Na_(2)CO_(3) and NaHCO_(3). 10 mL of the solution required 2.5 mL "of" 0.1M H_(2)SO_(4) for neutralisation using phenolphthalein as indicator. Methyl orange is then added when a further 2.5 mL "of" 0.2M H_(2)SO_(4) was required. The amount of Na_(2)CO_(3) and NaHCO_(3) in 1 "litre" of the solution is:

    A
    `5.3 g` and `4.2 g`
    B
    `3.3 g` and `6.2 g`
    C
    `4.2 g` and `5.3 g`
    D
    `6.2 g` and `3.3 g`
  • A solution contains Na_(2)CO_(3) " and " NaHCO_(3) , 10 mL of this solution required 2.5 mL of 0.1 M H_(2)SO_(4) for neutralisation using phenolphthalein indicator. Methyl orange is added after first end point, further titration required 2.5 mL of 0.2 M H_(2)SO_(4) . The amount of Na_(2)CO_(3) " and " NaHCO_(3) in 1 litre of the solution is :

    A
    5.3 g and 4.2 g
    B
    3.3 g and 6.2 g
    C
    4.2 g and 5.3 g
    D
    6.2 g and 3.3 g
  • Similar Questions

    Explore conceptually related problems

    A solution contians Na_(2)CO_(3) and NaHCO_(3), 20cm^(3) of this solution requires 5.0 cm^(3) of 0.1 M H_(2)SO_(4) Solution for neutralization using phenolphthalein as the indicator. Methylorange is then added when a further 5.0cm^(3) of 0.2 M H_(2)SO_(4) was required. Calculate the masses of Na_(2)CO_(3) and NaHCO_(3) is 1L of this solution.

    A solution contained Na_(2)CO_(3) and NaHCO_(3) . 25 mL of this solution required 5 mL 0.1 N HCl for titration with phenophthalein as indicator . The titration was repeated with the same volume of the solution but woth methyl orange .12.5 mL of 0.1 N HCl was required this time . Calculate the amount of Na_(2)CO_(3) and naHCO_(3) in the solution .

    A solution contains Na_(2)CO_(3) and NaHCO_(3) . 20 ml of this solution required 4 ml of 1 N HCl for titration with Ph indicator. The titration was repeated with the same volume of the solution but with MeOH. 10.5 ml of 1 N HCl was required this time. Calculate the amount of Na_(2)CO_(3) & NaHCO_(3) .

    0.1g of a solution containing Na_(2)CO_(3) and NaHCO_(3) requires 10mL of 0.01 N HCl for neutralization using phenolphthalein as an indicator, mass% of Na_(2)CO_(3) in solution is:

    A solution containing Na_(2)CO_(3) and NaOH requires 300 mL of 0.1 N HCl using phenolphthalein as an indicator. Methyl orange is then added to above titrated solution when a further 25 mL of 0.2 M HCl is required. The amount of NaOH present in the original solution is