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The value of n in the equation, Cr(2)O...

The value of n in the equation,
`Cr_(2)O_(7)^(2-) +14 H^(+)+ne^(-) to 2Cr^(3+) + 7H_(2)O` is :

A

2

B

3

C

4

D

6

Text Solution

Verified by Experts

The correct Answer is:
D
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Explore conceptually related problems

Consider the reaction : Cr_(2)O_(7)^(2-) + 14H^(+) + 6e^(-) to 2Cr^(3+) + 7H_(2)O What is the quantity of electricity in coulombs needed to reduce 1 mol of Cr_(2)O_(7)^(2-) ?

Consider the reaction : Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-) to 2Cr^(3+)+7H_(2)O What is the quantity of electricity in coulombs needed to reduce 1 mole of Cr_(2)O_(7)^(2-) ions ?

Knowledge Check

  • The value of n in the following equation is Cr_(2)O_(7)^(2-)+14H^(+)+"ne"to2Cr^(3+)+7H_(2)O+

    A
    6
    B
    2
    C
    3
    D
    4

  • The values of n in the following equation is Cr_(2)O_(7)^(2-) + 14H^(+) + nFe^(2+) to 2Cr^(3-) + nFe^(3+) + 7H_(2)O

    A
    4
    B
    3
    C
    7
    D
    6

  • Consider the reaction, Cr_(2)O_(7)^(2-)+ 14H^(+) + 6e^(-) to 2 Cr^(3+) + 7H_(2)O What is the quantity of electricity in coulombs needed to reduce 1 mole of 2 Cr_(2)O_(7)^(2-) ? (Given 1F= 96500C)

    A
    `5.79 xx 10^(5)`
    B
    `5.69 xx 10^(5)`
    C
    `5.59 xx 10^(5)`
    D
    `5.49 xx 10^(5)`

    • Similar Questions

    Explore conceptually related problems

    Consider the reaction : Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-) rarr 2Cr^(3+)+7H_(2)O What is the quantity of electricity in coulombs needed to reduce 1 mol e of Cr_(2)O_(7)^(2-) ?

    Complete the chemical equations : Cr_2O_7^(2-) + H^(+) + I^(-) to

    In the following reaction Cr_(2) O_(7)^(2-) + 14H^(+) + 6I^(-) rarr 2Cr^(3+) + 7H_(2)O + 3I_(2) Which element gets reduced ?

    In acidic medium potassium dichromate acts as on oxidant according to the equation, Cr_(2) O + 14 H^(+) + 6e^(-)rarr 2Cr^(3+) + 7H_(2)O . What is the equivalent weight of K_(2) Cr_(2) O_(7) ? (mol. Wt. = M)

    When the equation: Cr_(2)O_(7)^(2-) + H^(+) + I^(-) to Cr^(3+) + I_(2) is balanced the correct coefficient for I^(-) (aq) is :

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