A cork of mass 10 g is floating on water. The net force acting on the cork is

Options

A. 10N
B. `10^(-3)N`
C. `10^(-2)N`
D. zero

Explanation

To find the net force acting on a cork of mass 10 g that is floating on water, we can follow these steps:

### Step 1: Identify the forces acting on the cork
When the cork is floating, there are two main forces acting on it:
1. The gravitational force (weight) acting downward, which is given by \( F_g = mg \).
2. The buoyant force (thrust) acting upward, which is equal to the weight of the water displaced by the cork.

### Step 2: Calculate the weight of the cork
The weight of the cork can be calculated using the formula:
\[ F_g = mg \]
Where:
- \( m = 10 \, \text{g} = 0.01 \, \text{kg} \) (converting grams to kilograms)
- \( g = 9.81 \, \text{m/s}^2 \) (acceleration due to gravity)

Calculating the weight:
\[ F_g = 0.01 \, \text{kg} \times 9.81 \, \text{m/s}^2 = 0.0981 \, \text{N} \]

### Step 3: Understand the buoyant force
According to Archimedes' principle, the buoyant force acting on the cork is equal to the weight of the water displaced by the cork. Since the cork is floating, the buoyant force \( F_b \) is equal to the weight of the cork:
\[ F_b = F_g \]

### Step 4: Apply Newton's second law
The net force \( F_{net} \) acting on the cork can be calculated using Newton's second law:
\[ F_{net} = F_b - F_g \]
Since \( F_b = F_g \):
\[ F_{net} = F_g - F_g = 0 \]

### Conclusion
The net force acting on the cork is \( 0 \, \text{N} \).

### Final Answer
The net force acting on the cork is \( 0 \, \text{N} \).

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