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A metre stick weighing 600 g, is displac...

A metre stick weighing 600 g, is displaced through an angle of `60^@` in vertical plane as shown. The change in its potential energy is (`g = 10 m s^(-2)`)

A

1.5 J

B

15 J

C

30 J

D

45 J

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaU=(MgL)/2 (1-cos theta)=(600xx10xx1)/(1000xx2)xx1/2`
`DeltaU=6/4=1.5 J`
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