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A metre stick weighing 600 g, is displac...

A metre stick weighing 600 g, is displaced through an angle of `60^@` in vertical plane as shown. The change in its potential energy is (`g = 10 m s^(-2)`)

A

1.5 J

B

15 J

C

30 J

D

45 J

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaU=(MgL)/2 (1-cos theta)=(600xx10xx1)/(1000xx2)xx1/2`
`DeltaU=6/4=1.5 J`
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Knowledge Check

  • A stick of mass m and length l is pivoted at one end and is displaced through an angle theta. The increase in potential energy is

    A
    `mg(l)/(2)(1-cos theta)`
    B
    `mg(l)/(2)(1+cos theta)`
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    `mg(l)/(2)(1-sin theta)`
    D
    `mg(l)/(2)(1+sin theta)`

  • A simple pendulum of length 1m has bob of mass 100 g. It is displaced through an angle of 60^@ from the vertcal and then released. The kinetic energy of bob when it passes through the mean position is

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    `0.25J`
    B
    `0.5J`
    C
    `1.0J`
    D
    `1.4J`

  • In the arrangement as shown, tension T_(2) is - (g=10m//s^(2))

    A
    50 N
    B
    100 N
    C
    `50sqrt(3)N`
    D
    `100sqrt(3)N`

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