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A sample of an ideal gas occupies a volu...

A sample of an ideal gas occupies a volume V at pressure P and absolute temperature T. The mass of each molecule is m, then the density of the gas is

A

mKT

B

`(Pm)/(KT)`

C

`(P)/(km)`

D

`(P)/(KT)`

Text Solution

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The correct Answer is:
To find the density of an ideal gas, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Information**: - We have a sample of an ideal gas occupying a volume \( V \). - The pressure of the gas is \( P \). - The absolute temperature of the gas is \( T \). - The mass of each molecule of the gas is \( m \). 2. **Recall the Ideal Gas Law**: - The ideal gas law is given by the equation: \[ PV = nRT \] - Here, \( n \) is the number of moles, \( R \) is the universal gas constant, and \( T \) is the absolute temperature. 3. **Relate Moles to Mass**: - The number of moles \( n \) can be expressed in terms of the mass of the gas. If \( M \) is the total mass of the gas, then: \[ n = \frac{M}{M_m} \] - Where \( M_m \) is the molar mass of the gas. In terms of the mass of each molecule \( m \), the total mass \( M \) can be expressed as: \[ M = N \cdot m \] - Here, \( N \) is the total number of molecules. 4. **Substituting into the Ideal Gas Law**: - Substitute \( n \) into the ideal gas equation: \[ PV = \frac{M}{M_m}RT \] - Rearranging gives: \[ M = \frac{PV \cdot M_m}{RT} \] 5. **Calculate Density**: - The density \( \rho \) of the gas is defined as mass per unit volume: \[ \rho = \frac{M}{V} \] - Substitute the expression for \( M \): \[ \rho = \frac{PV \cdot M_m}{RT \cdot V} \] - Simplifying this gives: \[ \rho = \frac{PM_m}{RT} \] 6. **Expressing Molar Mass**: - The molar mass \( M_m \) can also be expressed in terms of the mass of a single molecule \( m \) and Avogadro's number \( N_A \): \[ M_m = N_A \cdot m \] - Substitute this back into the density equation: \[ \rho = \frac{P(N_A \cdot m)}{RT} \] 7. **Final Density Expression**: - Thus, the density of the ideal gas can be expressed as: \[ \rho = \frac{Pm}{kT} \] - Where \( k \) is the Boltzmann constant, which relates the temperature to the energy of the gas molecules. ### Final Answer: The density of the ideal gas is given by: \[ \rho = \frac{Pm}{kT} \]

To find the density of an ideal gas, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Information**: - We have a sample of an ideal gas occupying a volume \( V \). - The pressure of the gas is \( P \). - The absolute temperature of the gas is \( T \). ...
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Knowledge Check

  • A fiven sample of an ideal gas occupise a volume V at a pressure p and sbsoulte temperature T.The mass of each molecule of the gas is m. Which of the following fives the dinsity of the gas ?

    A
    p/(Kt)
    B
    pm/(kT)
    C
    p/(kTV)
    D
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  • A sample of a perfect gas occupies a volume V at a pressure P and obsolete temperature T. The mass of each molecules is m, which of the following expression given the number of molecules in the sample?

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    B
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    C
    `(m)/(k)`
    D
    `(PV)/(kT)`
  • A given sample of an ideal gas occupies a volume pressrue P and absolute temperature T. The mass of molecules of the gas is m. Which of the following density of the gas?

    A
    `P//(kTV)`
    B
    ` mkT `
    C
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