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The coefficient of volume expansion of ...

The coefficient of volume expansion of liquid is `gamma`. The fractional change in its density for `DeltaT` rise in temperature is

A

`gammaDeltaT`

B

`(DeltaT)/(gamma)`

C

`1+ gamma Deltat`

D

`1- gamma DeltaT`

Text Solution

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The correct Answer is:
To find the fractional change in density of a liquid when the temperature rises by \( \Delta T \), we can follow these steps: ### Step 1: Understand the relationship between volume and temperature The volume expansion of a liquid due to a temperature change is described by the formula: \[ V = V_0 (1 + \gamma \Delta T) \] where: - \( V \) is the final volume, - \( V_0 \) is the initial volume, - \( \gamma \) is the coefficient of volume expansion, - \( \Delta T \) is the change in temperature. ### Step 2: Relate density to volume Density (\( d \)) is defined as mass (\( m \)) divided by volume (\( V \)): \[ d = \frac{m}{V} \] Since mass remains constant during the temperature change, we can express the initial density (\( d_0 \)) and the final density (\( d \)) as follows: \[ d_0 = \frac{m}{V_0} \] \[ d = \frac{m}{V} \] ### Step 3: Substitute the volume expansion into the density formula Using the volume expansion formula, we can express the final density in terms of the initial density: \[ d = \frac{m}{V_0 (1 + \gamma \Delta T)} = \frac{d_0 V_0}{V_0 (1 + \gamma \Delta T)} = \frac{d_0}{1 + \gamma \Delta T} \] ### Step 4: Calculate the change in density The change in density (\( \Delta d \)) can be expressed as: \[ \Delta d = d - d_0 = \frac{d_0}{1 + \gamma \Delta T} - d_0 \] To combine these terms, we can find a common denominator: \[ \Delta d = d_0 \left( \frac{1}{1 + \gamma \Delta T} - 1 \right) = d_0 \left( \frac{1 - (1 + \gamma \Delta T)}{1 + \gamma \Delta T} \right) = d_0 \left( \frac{-\gamma \Delta T}{1 + \gamma \Delta T} \right) \] ### Step 5: Find the fractional change in density The fractional change in density is given by: \[ \text{Fractional change} = \frac{\Delta d}{d_0} = \frac{-\gamma \Delta T}{1 + \gamma \Delta T} \] For small values of \( \gamma \Delta T \), we can approximate \( 1 + \gamma \Delta T \approx 1 \), leading to: \[ \text{Fractional change} \approx -\gamma \Delta T \] ### Conclusion Thus, the fractional change in density for a rise in temperature \( \Delta T \) is approximately: \[ \text{Fractional change in density} \approx -\gamma \Delta T \] ### Final Answer The correct option is: \[ \text{Option D: } 1 - \gamma \Delta T \]
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The coefficient of volume expansion of a liquid is 4.9xx10^(-4)K^(-1) . Calculate the fractional change in its density when the temperature is raised by 30^(@)C .

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Knowledge Check

  • Choose the most appropriate option. The coefficient of volume expansion of glycerine is 49 xx 10^(-5)K^(-1) . What is the fractional change in its density for a 30^(@)C rise in temperature?

    A
    `1.5 xx 10^(-2)`
    B
    `2 xx 10^(-4)`
    C
    `3.5 xx 10^(-3)`
    D
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  • The value of coefficient of volume expansion of glycerin is 5 xx 10^(-4) K^(-1) . The fractional change in the density of glycerin for a rise of 40^(@)C in its temperature is

    A
    `0.010`
    B
    `0.015`
    C
    `0.020`
    D
    `0.025`
  • The value of coefficient of volume expansion of glycerin is 5xx10^(4)K^(-1) . The fractional change in temperature is :

    A
    `0.010`
    B
    `0.015`
    C
    `0.020`
    D
    `0.025`
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