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A current in a wire is given by the equa...

A current in a wire is given by the equation, . `I=2t^(2)-3t+1`, the charge through cross section of : wire in time interval t=3s to t=5s is

A

32.33C

B

43.34C

C

45.5C

D

42C

Text Solution

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The correct Answer is:
To find the charge that passes through a cross-section of the wire from time \( t = 3 \) seconds to \( t = 5 \) seconds, we start with the given current equation: \[ I = 2t^2 - 3t + 1 \] The relationship between current \( I \) and charge \( Q \) is given by: \[ I = \frac{dQ}{dt} \] To find the charge \( Q \) that flows through the wire during the specified time interval, we need to integrate the current with respect to time: \[ Q = \int_{t_1}^{t_2} I \, dt \] where \( t_1 = 3 \) seconds and \( t_2 = 5 \) seconds. Thus, we can express the charge as: \[ Q = \int_{3}^{5} (2t^2 - 3t + 1) \, dt \] Now, we will compute the integral: 1. **Integrate the function**: \[ \int (2t^2 - 3t + 1) \, dt = \frac{2}{3}t^3 - \frac{3}{2}t^2 + t + C \] 2. **Evaluate the definite integral from 3 to 5**: \[ Q = \left[ \frac{2}{3}t^3 - \frac{3}{2}t^2 + t \right]_{3}^{5} \] 3. **Calculate at the upper limit \( t = 5 \)**: \[ Q(5) = \frac{2}{3}(5^3) - \frac{3}{2}(5^2) + 5 \] \[ = \frac{2}{3}(125) - \frac{3}{2}(25) + 5 \] \[ = \frac{250}{3} - \frac{75}{2} + 5 \] \[ = \frac{250}{3} - \frac{225}{6} + \frac{30}{6} \] \[ = \frac{250}{3} - \frac{195}{6} \] \[ = \frac{500}{6} - \frac{195}{6} = \frac{305}{6} \] 4. **Calculate at the lower limit \( t = 3 \)**: \[ Q(3) = \frac{2}{3}(3^3) - \frac{3}{2}(3^2) + 3 \] \[ = \frac{2}{3}(27) - \frac{3}{2}(9) + 3 \] \[ = \frac{54}{3} - \frac{27}{2} + 3 \] \[ = 18 - \frac{27}{2} + 3 \] \[ = 21 - \frac{27}{2} = \frac{42}{2} - \frac{27}{2} = \frac{15}{2} \] 5. **Now, subtract the two results**: \[ Q = Q(5) - Q(3) = \frac{305}{6} - \frac{15}{2} \] \[ = \frac{305}{6} - \frac{45}{6} = \frac{260}{6} = \frac{130}{3} \] Thus, the total charge that passes through the cross-section of the wire from \( t = 3 \) seconds to \( t = 5 \) seconds is: \[ Q = \frac{130}{3} \text{ Coulombs} \approx 43.33 \text{ Coulombs} \]

To find the charge that passes through a cross-section of the wire from time \( t = 3 \) seconds to \( t = 5 \) seconds, we start with the given current equation: \[ I = 2t^2 - 3t + 1 \] The relationship between current \( I \) and charge \( Q \) is given by: ...
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