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In DeltaPQR,Pq=PR and S is the mid-point...

In `DeltaPQR,Pq=PR` and S is the mid-point of PQ. A line drawn from S parallel to QR, intersects the line PR at T. Prove that PS = PT.

Answer

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PQR is a triangle in which PQ=PR and S is any point on the side PQ. Through S, a line is drawn parallel to QR and intersecting PR at T. Prove that PS=PT

PQR is a triangle is which PQ=PR and S is any point on the side PQ. Through S, a line is drawn parallel to QR and intersecting PR at T. Prove that PS=PT

Knowledge Check

  • In DeltaPQR , QR=10, RP=11 and PQ=12. D is the midpoint of PR, DE is drawn parallel to PQ meeting QR in E. EF is drawn parallel to RP meeting PQ in F. What is the length of DF?

    A
    `(11)/(2)`
    B
    6
    C
    `(33)/(4)`
    D
    5

  • If S is the midpoint of a straight line PQ and R is a point different from S , such that PR = RQ , then

    A
    `anglePRS = 90^(@)`
    B
    `angleQRS = 90^(@)`
    C
    `anglePSR= 90^(@)`
    D
    `angleQSR lt 90^(@)`

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    If S is the mid-point of side QR of a DeltaPQR , then prove that PQ+PR=2PS .

    In DeltaPQR, point S is the midoint of side QR. If PQ =11, PR=17, PS=13, Find QR.

    In parallelogram PQRS, O is the mid point of SQ. Find angle S, angle R, PQ, QR and diagonal PR.

    If S is the midpoint of a straight line PQ and R is a point different from S, such that PR = RQ then

    If Q is a point on the side SR of a triangle PSR such that PQ=PR then prove that PS > PQ

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