Make correct statements by filling in the symbols `sub` or `cancel(sub)` in the blanks spaces : (i) `{2,3,4}…{1,2,3,4,5}`
(ii) `{a,b,c} …. {b,c,d}`
(iii) {x : x is a student of Class XI of your school}…{x : x student of your school}
(iv) {x : x is a circle in the plane with radius 1 unit}
(v) {x : x is a triangle in a plant}... {x : x is a rectangle in the plane}
(vi) {x : x is an equililateral triangle in a plane} .... {x : x is a triangle in the same plane}
(viii) {x : x is an even natural number} ... {x : x is an integer}.

Explanation

(i) `because` Each element of `{2,3,4}` is in the set `{1,2,3,4,5} and {2,3,4} ne {1,2,3,4,5}` ,
Therefore, `{2,3,4} sub {1,2,3,4,5}`
(ii) `because` a is an element of set (a, b, c) and `a in {b,c,d}`, therefore, `(a,b,c) cancel(sub) {b,c,d}`
(iii) Here, each element of first set in the elements of second set
Therefore, {x : x is a student of class XI of your school} `sub` {x : x is a student of your school}
(iv) {x : x is a circle in the plant} is a general set while the range of the elements of second set is finite
Therefore, {x : x is a circle in tha plane} `cancel sub` {x : x is a circle in the same plane with radius 1 unit}
(v) Here, it is clear that set of triangles and set of rectangles are different, so
{x : x is a triangle in a plane} `cancel(sub)` {x : x is a rectangle in the plane}
(vi) Here it is clear that each element of first set is also an element of second, set, therefore
{x : x is an equililateral triangle in a plane} `sub` {x : x is a triangle in the plane}
(vii) {x : x is a natural number}
`={2,4,6,8,...}`
{x : x is an integer} = {...., -4,-3,-2,-1,0,1,2,3,4,5,6,...}
Here, it is clear that all elements of first set are also the elements of second set. Therefore,
{x : x is an even natural number} `sub` {x : x is an integer}.