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The conjugate of the complex number (a+i...

The conjugate of the complex number `(a+ib)` is :

A

`-a-ib`

B

`-a+ib`

C

`a-ib`

D

None of these

Text Solution

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The correct Answer is:
To find the conjugate of the complex number \( z = a + ib \), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Complex Number**: The given complex number is \( z = a + ib \), where \( a \) is the real part and \( b \) is the imaginary part. 2. **Define the Conjugate**: The conjugate of a complex number \( z \) is denoted as \( \overline{z} \) and is defined as the real part minus the imaginary part. 3. **Apply the Definition**: For the complex number \( z = a + ib \): - The real part is \( a \). - The imaginary part is \( b \). Therefore, the conjugate \( \overline{z} \) can be expressed as: \[ \overline{z} = \text{Real part} - i \times \text{Imaginary part} = a - ib \] 4. **Write the Final Answer**: Thus, the conjugate of the complex number \( a + ib \) is: \[ \overline{z} = a - ib \] ### Final Answer: The conjugate of the complex number \( a + ib \) is \( a - ib \). ---
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Knowledge Check

  • The conjugate of the complex number ((1+i)^2)/(1-i) is

    A
    `1-i`
    B
    `1+i`
    C
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    D
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    B
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  • The conjugate of a complex number is (1)/( i - 1) . Then the complex number is :

    A
    `(-1)/(i - 1)`
    B
    `(1)/( i + 1)`
    C
    `(-1)/( i + 1)`
    D
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