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If N(A) is Avogadro's number, then the n...

If `N_(A)` is Avogadro's number, then the number of oxygen atom in one g-equivalent of oxygen is

A

`N_(A)`

B

`N_(A)//2`

C

`N_(A)//4`

D

`2N_(A)`

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The correct Answer is:
To find the number of oxygen atoms in one gram equivalent of oxygen, we will follow these steps: ### Step 1: Understand the concept of gram equivalent A gram equivalent (g-equivalent) is defined as the amount of substance that will react with or replace one mole of hydrogen atoms or one mole of electrons in a reaction. For an element, it can be calculated using the formula: \[ \text{Gram Equivalent} = \frac{\text{Mass of substance}}{\text{Equivalent weight of substance}} \] ### Step 2: Determine the equivalent weight of oxygen The equivalent weight of an element can be calculated using the formula: \[ \text{Equivalent weight} = \frac{\text{Molar mass}}{n} \] Where: - Molar mass of oxygen (O) = 16 g/mol - The n factor for oxygen (in the context of forming O2) is 2 (since one mole of O2 contains two moles of oxygen atoms). Thus, the equivalent weight of oxygen is: \[ \text{Equivalent weight of oxygen} = \frac{16 \text{ g/mol}}{2} = 8 \text{ g/equiv} \] ### Step 3: Calculate the mass of oxygen in one gram equivalent Since we are considering one gram equivalent of oxygen, we have: \[ \text{Mass of oxygen} = \text{Equivalent weight} = 8 \text{ g} \] ### Step 4: Calculate the number of moles of oxygen Now, we can calculate the number of moles of oxygen in 8 grams using the formula: \[ \text{Number of moles} = \frac{\text{Mass}}{\text{Molar mass}} = \frac{8 \text{ g}}{16 \text{ g/mol}} = 0.5 \text{ moles} \] ### Step 5: Calculate the number of oxygen atoms To find the number of atoms, we use Avogadro's number (N_A), which is approximately \(6.022 \times 10^{23}\) atoms/mol. The number of atoms in 0.5 moles of oxygen is: \[ \text{Number of atoms} = \text{Number of moles} \times N_A = 0.5 \times N_A = \frac{N_A}{2} \] ### Conclusion Thus, the number of oxygen atoms in one gram equivalent of oxygen is: \[ \frac{N_A}{2} \]

To find the number of oxygen atoms in one gram equivalent of oxygen, we will follow these steps: ### Step 1: Understand the concept of gram equivalent A gram equivalent (g-equivalent) is defined as the amount of substance that will react with or replace one mole of hydrogen atoms or one mole of electrons in a reaction. For an element, it can be calculated using the formula: \[ \text{Gram Equivalent} = \frac{\text{Mass of substance}}{\text{Equivalent weight of substance}} \] ...
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Knowledge Check

  • Avogadro's number N_(A) is

    A
    `6.02 xx 10^(-23)`
    B
    `6.02 xx 10^(23)`
    C
    `8.31 xx 10^(23)`
    D
    none of these
  • Atoms and molecules are so small in size that it is neither possible to count them individually nor possible to determine their mass. These are counted collectively in terms of Avogadro's number. The mass of Avogadro's number of atoms and molecules is known as gram atomic mass and gram molecular mass respectively. The volume occupied by Avogadro's number of molecules of a gas or vapours is known as molar volume. If N_(A) is Avogadro's number, then the number of valence electrons in 4.2 g of nitride ions (N^(3-)) is :

    A
    `4.2 N_(A)`
    B
    `2.4 N_(A)`
    C
    `1.6 N_(A)`
    D
    `3.2 N_(A)`
  • If N is Avogadro's number, then the number of molecules in 6 g of hydrogen at NTP is

    A
    `2 N`
    B
    `3 N`
    C
    `N`
    D
    `N//6`
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