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Molar conductance of a solution is given...

Molar conductance of a solution is given by the expression
`^^m = (kxx1000mLL^(-1))/(c)`
Here c is the concentration in mol `L^(-1)` and k is expressed in `ohm^(-1) cm^(-1)`. Units of molar conductance are

A

`ohm mol^(-1)`

B

`Ohm cm^(-1) mol^(-1)`

C

`ohm cm^(2) mol`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
Units of `^^_(m) = ("Units of K"xx1000mL)/(1Lxx"units of c")`
`= (ohm^(-1)cm^(-1)xxmL)/(1Lxxmol L^(-1))`
`= (ohm^(-1)cm^(-1)xxcm^(3))/(mol)" "[:' 1 mL = 1 cm^(3)]`
`ohm^(-1)cm^(2)mol^(-1)`
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Knowledge Check

  • The molar conductance is given by the relation (M = concentration in molarity)

    A
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    B
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    A
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    B
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    A
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