Molar conductance of a solution is given by the expression
`^^m = (kxx1000mLL^(-1))/(c)`
Here c is the concentration in mol `L^(-1)` and k is expressed in `ohm^(-1) cm^(-1)`. Units of molar conductance are

Options

A. `ohm mol^(-1)`
B. `Ohm cm^(-1) mol^(-1)`
C. `ohm cm^(2) mol`
D. None of these

Answer

A

Explanation

Units of `^^_(m) = ("Units of K"xx1000mL)/(1Lxx"units of c")`
`= (ohm^(-1)cm^(-1)xxmL)/(1Lxxmol L^(-1))`
`= (ohm^(-1)cm^(-1)xxcm^(3))/(mol)" "[:' 1 mL = 1 cm^(3)]`
`ohm^(-1)cm^(2)mol^(-1)`