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8.34 g of a divalent metal is oxidised b...

8.34 g of a divalent metal is oxidised by 0.680 L of oxygen (in standard conditions). Hence, atomic mass of the metal is

A

`68.7`

B

`34.3`

C

`137.4`

D

`274.7`

Text Solution

Verified by Experts

The correct Answer is:
C
`22.4L` of oxygen at S.T.P. = 32 g
0.680 L of oxygen at S.T.P.
`=(32)/(22.4)xx0.680 = 0.971 g`
0.971 g of oxygen reacts with 8.34 g of metal 8 g oxygen reacts with `(8.34g)/(0.971g)xx8g = 68.71`
`:.` At mass of metal `= "Eq. mass"xx"valency"`
`= 68.71xx2 = 137.42`
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