Total number of electrons present in 18 mL of water (density of water is 1 g/mL) is

Options

A. `6.02xx10^(23)`
B. `6.02xx10^(22)`
C. `6.02xx10^(24)`
D. `6.02xx10^(25)`

Explanation

To find the total number of electrons present in 18 mL of water, we can follow these steps:

### Step 1: Calculate the mass of water
Given that the density of water is 1 g/mL, we can calculate the mass of 18 mL of water using the formula:

\[ \text{Mass} = \text{Density} \times \text{Volume} \]

Substituting the values:

\[ \text{Mass} = 1 \, \text{g/mL} \times 18 \, \text{mL} = 18 \, \text{g} \]

### Step 2: Calculate the number of moles of water
To find the number of moles of water, we use the molar mass of water (H₂O), which is approximately 18 g/mol.

\[ \text{Number of moles} = \frac{\text{Mass}}{\text{Molar mass}} = \frac{18 \, \text{g}}{18 \, \text{g/mol}} = 1 \, \text{mol} \]

### Step 3: Calculate the number of water molecules
Using Avogadro's number (approximately \(6.02 \times 10^{23}\) molecules/mol), we can find the total number of water molecules in 1 mole:

\[ \text{Number of molecules} = 1 \, \text{mol} \times 6.02 \times 10^{23} \, \text{molecules/mol} = 6.02 \times 10^{23} \, \text{molecules} \]

### Step 4: Calculate the total number of electrons in water
Each water molecule (H₂O) contains:
- 2 electrons from the two hydrogen atoms (H)
- 8 electrons from the one oxygen atom (O)

Thus, the total number of electrons in one water molecule is:

\[ \text{Total electrons per molecule} = 2 + 8 = 10 \, \text{electrons} \]

Now, we can find the total number of electrons in 18 mL of water:

\[ \text{Total electrons} = \text{Number of molecules} \times \text{Electrons per molecule} = 6.02 \times 10^{23} \, \text{molecules} \times 10 \, \text{electrons/molecule} \]

\[ \text{Total electrons} = 6.02 \times 10^{24} \, \text{electrons} \]

### Final Answer
The total number of electrons present in 18 mL of water is \(6.02 \times 10^{24}\) electrons.

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