Addition of HBr to 2-methyl1-prop-1ene in the presence of hydrogen peroxide mainly forms

Options

A. 1-Bromobutane
B. 2-Bromopropane
C. 2-Bromo-2-methylpropane
D. 1-Bromo-2-methylpropane

Explanation

To solve the question regarding the addition of HBr to 2-methylprop-1-ene in the presence of hydrogen peroxide, we will follow these steps:

### Step 1: Identify the Structure of 2-Methylprop-1-ene
2-Methylprop-1-ene is an alkene with the following structure:
- The main chain is a propene (3 carbon atoms) with a methyl group (–CH3) attached to the second carbon.
- The structure can be represented as:

```
CH3
|
CH2=C-CH3
|
H
```

### Step 2: Understand the Reaction Conditions
The reaction involves the addition of HBr (hydrobromic acid) in the presence of hydrogen peroxide (H2O2). The presence of H2O2 indicates that the reaction will follow an anti-Markovnikov addition mechanism.

### Step 3: Apply Anti-Markovnikov's Rule
In anti-Markovnikov addition, the hydrogen atom from HBr will attach to the carbon atom that has the lesser number of hydrogen atoms (the less substituted carbon). In our case:
- The double bond is between the first and second carbon atoms.
- The first carbon (C1) has two hydrogen atoms, while the second carbon (C2) has one hydrogen atom and one methyl group.

### Step 4: Determine the Product
According to anti-Markovnikov's rule:
- The hydrogen (H) from HBr will add to the second carbon (C2), which has fewer hydrogen atoms.
- The bromine (Br) will then attach to the first carbon (C1).

This results in the formation of 1-bromo-2-methylpropane. The structure of the product can be represented as:

```
CH3
|
CH2-Br
|
CH3
```

### Step 5: Final Answer
The main product formed from the addition of HBr to 2-methylprop-1-ene in the presence of hydrogen peroxide is **1-bromo-2-methylpropane**.

### Summary of Options
- Option 1: 1-bromobutane
- Option 2: 2-bromopropane
- Option 3: 2-bromo-2-methylpropane
- Option 4: 1-bromo-2-methylpropane (Correct Answer)