Calculate the uncertainty in the velocity of a particle of mass `1.1xx10^(-27)` kg if the uncertainty in the uncertainty in its position is `3xx10^(-10)cm`.

Answer

`1.6xx10^(4) m s^(-1)`

Explanation

According to uncertainty principle,
`Deltax*m Deltav=(h)/(4pi) or Deltav=(h)/(4pimDeltax)`
`Deltax=3xx10^(-10)=3xx10^(-12)m, m=1.1xx10^(-27) "kg" , pr=3.143`,
`h=6.626xx10^(-34) "kg"m^(2)s^(-1)"`
`Deltav=((6.626xx10^(-34)"kg"m^(2)s^(-1)))/(4xx3.143xx(1.1xx10^(-27)"kg")xx(3xx10^(-12)m))=1.6xx10^(4)ms^(-1)`.