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Explain how an electron can be considere...

Explain how an electron can be considered to have a particle as well as a wave nature. Using Planck's equation, E=hv and Einstein's equation `E=mc^(2)`, deduce de Broglie relation for a photon.

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In the photoelectric effect the eletrons are emiited intantaneously from a given matal plate when it is irradiated with radiation of frequency equal to or greater then some minimum ferquency, is called the threshold frequency.According to Planck's idea, light may be considered to be made up discrete particles called photons.Each photon carries energy equal ti hv.When this photon cllides with the electron of the metal, the electron acquires energy of the emitted electron is given by : hv=K.E_("maximum")+PE=(1)/(2)m u^(2)+PE If the incident rediation is of threshold frequency the electron will be emitted without any kinetic energy i.e hv_(0) :.(1)/(2)m u^(2)=hv-hv_(0) A plot of kinetic energy of the emitted electron versus frequency of the incident radiation yields a straight line given as : A beam of white light is dispersed into its wavelenght components of potassium metal. What of the electron emitted by the different light component ?

In the photoelectric effect the eletrons are emiited intantaneously from a given matal plate when it is irradiated with radiation of frequency equal to or greater then some minimum ferquency, is called the threshold frequency.According to Planck's idea, light may be considered to be made up discrete particles called photons.Each photon carries energy equal ti hv.When this photon cllides with the electron of the metal, the electron acquires energy of the emitted electron is given by : hv=K.E_("maximum")+PE=(1)/(2)m u^(2)+PE If the incident rediation is of threshold frequency the electron will be emitted without any kinetic energy i.e hv_(0) :.(1)/(2)m u^(2)=hv-hv_(0) A plot of kinetic energy of the emitted electron versus frequency of the incident radiation yields a straight line given as : The number of photoelectrons emitted depends upon :

In the photoelectric effect the eletrons are emiited intantaneously from a given matal plate when it is irradiated with radiation of frequency equal to or greater then some minimum ferquency, is called the threshold frequency.According to Planck's idea, light may be considered to be made up discrete particles called photons.Each photon carries energy equal ti hv.When this photon cllides with the electron of the metal, the electron acquires energy of the emitted electron is given by : hv=K.E_("maximum")+PE=(1)/(2)m u^(2)+PE If the incident rediation is of threshold frequency the electron will be emitted without any kinetic energy i.e hv_(0) :.(1)/(2)m u^(2)=hv-hv_(0) A plot of kinetic energy of the emitted electron versus frequency of the incident radiation yields a straight line given as : A laser producting monochromatic lights of different wavelenght is uesd to eject electrons from the sheet of glod having threshold frequency 6.15xx10^(14)s^(-1) Which of the following incident rediation will be suitable for the ejecting of electrons ?

According to Louis de Broglie, a French physicist, every moving material particle has a dual nature i.e., wave and particle nature. The two characters are co-related by de Broglie relation lambda=(h)/(m upsilon(p)). Here lambda represents wave nature while p or m upsilon accounts for the particle nature. Since h is constant , the two characters are inversely proportional to each other. This relationship or equation is valid mainly for microscopic particles such as electrons, protons, atoms, ions, molecules etc. It does not apply to semi-micro or micro particles. For particles having same kinetic energy , the de Broglie wavelength is :

According to Louis de Broglie, a French physicist, every moving material particle has a dual nature i.e., wave and particle nature. The two characters are co-related by de Broglie relation lambda=(h)/(m upsilon(p)). Here lambda represents wave nature while p or m upsilon accounts for the particle nature. Since h is constant , the two characters are inversely proportional to each other. This relationship or equation is valid mainly for microscopic particles such as electrons, protons, atoms, ions, molecules etc. It does not apply to semi-micro or micro particles. If travelling at equal speeds, the longest wavelength of the following matter waves is for

According to Louis de Broglie, a French physicist, every moving material particle has a dual nature i.e., wave and particle nature. The two characters are co-related by de Broglie relation lambda=(h)/(m upsilon(p)). Here lambda represents wave nature while p or m upsilon accounts for the particle nature. Since h is constant , the two characters are inversely proportional to each other. This relationship or equation is valid mainly for microscopic particles such as electrons, protons, atoms, ions, molecules etc. It does not apply to semi-micro or micro particles. Which of the following is not correct ?

An electron, a proton and an alpha particle have kinetic energy of 16E,4E and E respectively. What is the qualitavtive order of their de Broglie wavelengths :-