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A Photon of red light having wavelength ...

A Photon of red light having wavelength 600 nm has energy equal of `(h=6.6xx10^(-34)Js)` :

A

`3.3xx10^(-19)J`

B

`1.0xx10^(-19)J`

C

`3.0xx10^(-18)J`

D

`1xx10^(19)J`

Text Solution

Verified by Experts

The correct Answer is:
A

`E=hv=h(c)/(lambda)`
`=((6.610^(-34)Js)xx(3xx10^(8)ms^(-1)))/((600xx10^(-9)m))`
`=3.3xx10^(-19)J`.
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Knowledge Check

  • If the mass of neutron is 1.7 xx 10^(-27) kg, then the de - Broglie wavelength of neutron of energy 3 eV is: (h = 6.6 xx 10^(-34) Js)

    A
    `1.4 xx 10^(-11) m`
    B
    `1.6 xx 10^(-10)m`
    C
    `1.65 xx 10^(-11)m`
    D
    `1.4 xx 10^(-10)m`
  • Calculate the energy in joule corresponding to light of wavelength 45 nm (Planck.s constant h=6.63xx10^(-34) Js, speed of light c=3xx10^(8) ms^(-2))

    A
    `6.67xx10^(12)`
    B
    `4.42xx10^(-13)`
    C
    `4.42xx10^(-18)`
    D
    `6.67xx10^(12)`
  • Calculate the energy in joule corresponding to light of wavelength 45 nm (Planck.s constant h=6.63xx10^(-34) Js, speed of light c=3xx10^(8) ms^(-2))

    A
    `6.67xx10^(12)`
    B
    `4.42xx10^(-13)`
    C
    `4.42xx10^(-18)`
    D
    `6.67xx10^(12)`
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