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A solution has been prepared by dissolvi...

A solution has been prepared by dissolving 0.063 g of `HNO_(3)` in 1000 mL of It . Calculate the `[H^(+)]` and `[OH^(-)]` of the solution.

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To solve the problem of calculating the concentrations of \([H^+]\) and \([OH^-]\) in a solution prepared by dissolving 0.063 g of \(HNO_3\) in 1000 mL of water, we can follow these steps: ### Step 1: Calculate the molar mass of \(HNO_3\) The molar mass of \(HNO_3\) can be calculated as follows: - Hydrogen (H) = 1 g/mol - Nitrogen (N) = 14 g/mol - Oxygen (O) = 16 g/mol × 3 = 48 g/mol ...
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Knowledge Check

  • A solution is prepared by dissolving 10 g of NaOH in 100 mL of solution. Its molarity is

    A
    1.0 M
    B
    2.5 M
    C
    1.5 M
    D
    4.0 M

  • A solution is prepared by dissolving 10 g of KOH in 100 ml of solution . Its molarity is

    A
    4.0 M
    B
    1 .09 M
    C
    1.78 M
    D
    2.50 M

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