`1 cm^(3)` of 0.01 N HCl solution is added to one litre of sodium chloride solution . Calculate the pH of the resulting solution.

Explanation

Since NaCI is a neutral salt, its solution as such will not give any `H^(+)` ions. It will dilute HCI solution.
Concentration of HCI before dilution =0.01 N
Concentration of HCI after dilution `=0.01//1000 = 10^(-5) N=10^(-5) M.` lt brgt (HCI is a monobasic acid. Its molarity and normality are the same)
`[H_(3)O^(+)] =10^(5) , pH =- log (10^(-5) M) =(-) (-5) log 10 =5`