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Reaction between ethyl acetate and water...

Reaction between ethyl acetate and water attains a state of equilibrium in an open vessel but not the decomposition of `CaCO_(3).` Explain.

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In the first case, the reactants as well as the products are liquids and they will not escape from the vessel even if it is open. Therefore both the forward and backwards reaction will take place simultaneously and equilibrium will be reached. But in the decompositing of `CaCO_(3)` one of hte products is `CO_(2)`. Being a gas it will escape from the open vessel and the backward reaction will not take place. Therefore in the decompositing of `CaCO_(3)` equilibrium cannot be achieved.
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Reaction between acetic acid and ethyl alcohol attains a state of equilibrium in an open vessel but decomposition of CaCO_(3) does not. Why ?

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Knowledge Check

  • When 20 g of CaCO_3 were put into 10 litre flask and heated to 800^@C, 30% of CaCO_3 remained unreacted at equilibrium K_p for decomposition of CaCO_3 will be

    A
    1.145 atm
    B
    1.231 atm
    C
    2.146 atm
    D
    3.145 atm
  • Consider the reaction CaCO_(3)(s) hArr CaO(s) +CO_(2)(g) in closed container at equilibrium. What would be the effect of addition of CaCO_(3) on the equilibrium concentration of CO_(2) ?

    A
    Increase
    B
    Decreases
    C
    Remains unaffected
    D
    Data is not sufficient to predict it
  • 3.0 moles of PCl_(5) kept in 1 L closed reaction vessel was allowed to attain equilibrium at 380 K. The composition of the mixture i.e., PCl_(5) and PCl_(3) respectively at equilibrium

    A
    1.71, 2.25
    B
    1.59, 1.61
    C
    1.41, 1.59
    D
    1.41, 1.41
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    When 20 g of CaCO_(3) were put into 10 litre flask and heated to 800^(@)C , 35% of CaCO_(3) remained unreacted at equilibrium. K_(p) for decomposition of CaCO_(3) is :

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