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What is molality of 1 M solution of sodi...

What is molality of 1 M solution of sodium nitrate if its density is `1.25 "g cm"^(-3)` ?

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To find the molality of a 1 M solution of sodium nitrate (NaNO3) with a density of 1.25 g/cm³, we can follow these steps: ### Step 1: Understand the given information We have: - Molarity (M) = 1 M (which means 1 mole of solute per liter of solution) - Density of the solution = 1.25 g/cm³ ### Step 2: Calculate the volume of the solution ...
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Knowledge Check

  • What is the molarity of a 0.500 molal aqueous solution of calcium nitrate that has a density of 1.045gmL^(-1) ?

    A
    `0.483` M
    B
    `0.500` M
    C
    `0.522` M
    D
    `0.567` M

  • 30 g. of acetic acid is dissolved in 1 dm^(3) of a solvent. The molality of the solution will be (Givent, density of solvent =1.25 g cm^(-3)

    A
    `0.40`
    B
    `0.35`
    C
    `0.55`
    D
    `0.25`

  • The molality of 3M solution os mehtanol if the density of the solution is 0.9g cm^(-3) , is

    A
    3.73
    B
    `3.0`
    C
    3.33
    D
    3.1

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    The molality of 1 M solution of sodium nitrate is 0.858 mol kg^(-1) . Determine the density of the solution. How much BaCl_(2) would needed to make 250 L of a solution having same concetration of Cl^(ɵ) as the one containing 3.78 g of NaCl per 100 mL ?

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