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Calculate the molality of a solution con...

Calculate the molality of a solution containing 20.7 g of potassium carbonate in 500 mL of solution (assume density of solution `= "1g mL"^(-1)`)

Text Solution

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The correct Answer is:
0.313 m
Mass of 500 mL of the solution `= 500 xx 1 = 500 g`
Mass of solvent (water) `= 500 - 20.7 = 479.3 g = 0.4693 kg`
Molality of solution `(m)=((20.7g))/(("138 g mol"^(-1))xx("0.4793 kg"))=0.313 "mol kg"^(-1)=0.313` m.
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Knowledge Check

  • Calculate the molality of a solution containing 20.7 g potassium carbonate dissolved in 500mL of solution (assume density of solution =1 gmL^(-1) ).

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    B
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    ` 0.25 M, 0.25 N `
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  • What is the molarity of a solution containing 10 g of NaOH in 500 mL of solution ?

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