Calculate the molality of a solution containing 20.7 g of potassium carbonate in 500 mL of solution (assume density of solution `= "1g mL"^(-1)`)

Answer

0.313 m

Explanation

Mass of 500 mL of the solution `= 500 xx 1 = 500 g`
Mass of solvent (water) `= 500 - 20.7 = 479.3 g = 0.4693 kg`
Molality of solution `(m)=((20.7g))/(("138 g mol"^(-1))xx("0.4793 kg"))=0.313 "mol kg"^(-1)=0.313` m.