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Concentration of glucose (C(6)H(12)O(6))...

Concentration of glucose `(C_(6)H_(12)O_(6))` in normal blood is approximately 90 mg per 100 mL. What is the molarity of glucose in blood ?

Text Solution

Verified by Experts

The correct Answer is:
0.005 M
Mass of glucose = 90 mg `= (90)/(1000) = 0.09 g`
No. of moles of glucose `= ("Mass of glucose")/("Molar mass")=(("0.09 g"))/(("180 g mol"^(-1)))=0.005` mol
Volume of solution = 100 mL = 0.1 L
Molarity of solution (M) `= ("No. of moles of glucose")/("Volume of solution in litres")=(("0.005 mol"))/(("0.1 L"))="0.005 mol L"^(-1)=0.005M`
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Knowledge Check

  • If the concentration of glucose (C_(6)H_(12)O_(6)) in blood is 0.9 g L^(-1) . What will be the molarity of glucose in blood?

    A
    5M
    B
    50M
    C
    0.005M
    D
    0.5M

  • If the concentration of glucose (C_(6)H_(12)O_(6)) in blood is 0.9 "g L"^(-1) , what will be the molarity of glucose in blood ?

    A
    5 M
    B
    50 M
    C
    0.005 M
    D
    0.5 M

  • If the concentration of glucose (C_(6)H_(12)O_(6)) in blood is 0.9 g L^(-1) , what will be the molarity of glucose in blood?

    A
    5 M
    B
    50 M
    C
    0.005 M
    D
    0.5 M

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