Volume occupied by one molecule of water (density `"1 g cm"^(-3)`) is :

Options

A. `3.0 xx 10^(-23) cm^(3)`
B. `5.5 xx 10^(23) cm^(3)`
C. `9.0 xx 10^(-23) cm^(3)`
D. `6.023 xx 10^(-23) cm^(3)`

Answer

A

Explanation

Mass of one molecule of water
`= ((18g))/(6.022xx10^(23))=3xx10^(-23)g`
Since density of water is 1g
`:.` Volume occupied by one molecule of water
`= 3 xx 10^(-23)` cc.