Which has maximum number of atoms ?

Options

A. 24 g of C-12
B. 56g of Fe-56
C. 27 g of Al-27
D. 108 g of Ag-108

Explanation

To determine which of the given substances has the maximum number of atoms, we need to calculate the number of moles of each substance and then use Avogadro's number to find the total number of atoms.

### Step-by-Step Solution:

1. **Identify the Given Data**:
- 24 g of C (Carbon-12)
- 56 g of Fe (Iron-56)
- 27 g of Al (Aluminum-27)
- 108 g of Ag (Silver-108)

2. **Calculate the Number of Moles for Each Substance**:
- **For Carbon (C)**:
- Molar mass of C = 12 g/mol
- Number of moles = Given weight / Molar mass = 24 g / 12 g/mol = 2 moles

- **For Iron (Fe)**:
- Molar mass of Fe = 56 g/mol
- Number of moles = Given weight / Molar mass = 56 g / 56 g/mol = 1 mole

- **For Aluminum (Al)**:
- Molar mass of Al = 27 g/mol
- Number of moles = Given weight / Molar mass = 27 g / 27 g/mol = 1 mole

- **For Silver (Ag)**:
- Molar mass of Ag = 108 g/mol
- Number of moles = Given weight / Molar mass = 108 g / 108 g/mol = 1 mole

3. **Calculate the Number of Atoms**:
- Using Avogadro's number (Na = 6.022 x 10²³ atoms/mol):
- **For Carbon (C)**:
- Number of atoms = Number of moles × Na = 2 moles × 6.022 x 10²³ atoms/mol = 1.2044 x 10²⁴ atoms

- **For Iron (Fe)**:
- Number of atoms = 1 mole × Na = 1 × 6.022 x 10²³ atoms/mol = 6.022 x 10²³ atoms

- **For Aluminum (Al)**:
- Number of atoms = 1 mole × Na = 1 × 6.022 x 10²³ atoms/mol = 6.022 x 10²³ atoms

- **For Silver (Ag)**:
- Number of atoms = 1 mole × Na = 1 × 6.022 x 10²³ atoms/mol = 6.022 x 10²³ atoms

4. **Compare the Number of Atoms**:
- Carbon (C): 1.2044 x 10²⁴ atoms
- Iron (Fe): 6.022 x 10²³ atoms
- Aluminum (Al): 6.022 x 10²³ atoms
- Silver (Ag): 6.022 x 10²³ atoms

5. **Conclusion**:
- The substance with the maximum number of atoms is **24 g of Carbon-12**, which has **1.2044 x 10²⁴ atoms**.