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The rate constant for the reaction, 2N(2...

The rate constant for the reaction, `2N_(2)O_(5) rarr 4NO_(2) + O_(2)` is `3.0 xx 10^(-5) s^(-1)`. If the rate is `2.40 xx 10^(-5) mol L^(-1) s^(-1)`, then the initial concentration of `N_(2)O_(5)` (in `mol L^(-1)`) is

A

1.4

B

1.2

C

0.04

D

0.8

Text Solution

Verified by Experts

The correct Answer is:
D
d) The unit of rate constant (k) indicates reaction to be of first order.
`therefore` rate = `k[N_(2)O_(5)]`
`[N_(2)O_(5)] = ("Rate")/k = (2.4 xx 10^(-5)mol L^(-1)s^(-1))/(3.0 xx10^(-5)s)`=0.8
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Knowledge Check

  • The rate constant for the reaction 2N_(2)O_(5) rarr 4NO_(2)+O_(2) is 3.0 xx 10^(-5) s^(-1) . If the rate is 2.40 xx 10^(-5) mol L^(-1) s^(-1) , then the concentration of N_(2)O_(5) (in mol L^(-1) ) is

    A
    `1.4`
    B
    `1.2`
    C
    `0.04`
    D
    `0.8`

  • The rate constant for the reaction , 2N_(2)O_(5) to 4NO_(2) + O_(2) is 3 xx 10^(-5) sec^(-1) . If the rate is 2.40 xx 10^(-5) mol "litre"^(-1) sec^(-1) . Then the concentration of N_(2)O_(5) (in mol litre^(-1) ) is

    A
    `1.4`
    B
    1.2
    C
    `0.04`
    D
    `0.8`

  • The rate constant for the reaction: 2N_(2)O_(5) rarr 4NO_(2)+O_(2) is 3.0xx10^(-5) sec^(-1) . If the rate is 2.40xx10^(-5) M sec^(-1) , then the concentration of N_(2)O_(5) (in M) is:

    A
    (a) `1.4`
    B
    (b) `1.2`
    C
    (c ) `0.04`
    D
    (d) `0.8`

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