Home
Class 12
CHEMISTRY
A student suggested that calcium could b...

A student suggested that calcium could be obtained by reducing dolomite `(CaCO_(3).MgCO_(3))` with aluminium powder. Was he correct in his approach ?
(Given `Delta_(f)G^(@) (CaO)=-640.0 " kJ mol"^(-1), Delta_(f)G^(@) Al_(2)O_(3)(s)=-1580.0 " kJ mol"^(-1))`.

Text Solution

Verified by Experts

No, he was wrong in his approach as is evident from the value of `DeltaG^(@)` for the reaction :
`underset(("From dolomite"))(3CaO(s))+2Al(s) overset("heat") to Al_(2)O_(3) (s) +3Ca(s)`
`DeltaG^(@)= Delta_(f)G^(@)(Al_(2)O_(3))-3Delta_(f)G^(@)(CaO)`
`DeltaG^(@)=-1580-3(-640)=340 kJ=+ ve`

Since `DeltaG^(@)` comes out to be positive, the reaction is not feasible.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS

    DINESH PUBLICATION|Exercise N.C.E.R.T. Exemplar Problems|26 Videos
  • GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS

    DINESH PUBLICATION|Exercise Matching Type Questions|5 Videos
  • GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS

    DINESH PUBLICATION|Exercise Questions From Board Examinations|43 Videos
  • ETHERS

    DINESH PUBLICATION|Exercise (MCQs)|8 Videos
  • HALOALKANES AND HALOARENES

    DINESH PUBLICATION|Exercise Brain storming multiple choice questions|11 Videos

Similar Questions

Explore conceptually related problems

Will the reaction, I_(2)(s) +H_(2)S(g) rarr 2HI(g) +S(s) proceed spontaneously in the forward direction of 298K Delta_(f)G^(Theta)HI(g) = 1.8 kJ mol^(-1), Delta_(f)G^(Theta)H_(2)S(g) = 33.8 kJ mol^(-1) ?

Determine whether or not is possible for sodium to reduce aluminium oxide to aluminium at 298K . Also, calculate equilibrium constant for this reaction at 298K . Delta_(f)G^(Theta)AI_(2)O_(3)(s) =- 1582 kJ mol^(-1) Delta_(f)g^(Theta)Na_(2)O(s) =- 377.7 kJ mol^(-1)

Knowledge Check

  • The minimum voltage required to electrolyse alumina in the Half - Heroult process is Given, DeltaG_(f)^(@)(Al_(2)O_(3))=-1520 kJ mol^(-1) DeltaG_(f)^(@)(CO_(2))=-394 kJ mol^(-1)

    A
    1.575 V
    B
    1.60 V
    C
    1.312 V
    D
    `-2.62 V`
  • (A) Reduction of Cr_(2)O)(3) with the Aluminium is possible ( R ) DeltaG_((f))^(0) of Cr_(3)O_(3) " is -540kj//mole and" DeltaG_((f))^(0) of Al_(2)O_(3) is -827kj//"mole"

    A
    If both (A) and (R ) are correct and (R ) is the correct explantion of (A )
    B
    If both (A) and (R ) are correct and (R ) is not the correct explantion of (A )
    C
    If (A) is correct but (R ) is incorrect
    D
    If (A) is incorrect but (R ) is correct
  • What will be the heat of reaction for the following reaction? Will the reaction be exothermic or endothermic? Fe_(2)O_(3(s))+3H_(2(g))rarr 2Fe_((s))+3H_(2)O_((l)) Delta_(f)H^(@)(H_(2)O,l)=-"285.83 kJ mol"^(-1) Delta_(f)H^(@)(Fe_(2)O_(3),s)=-"824.2 kJ mol"^(-1)

    A
    `-"824. 2 kJ mol"^(-1),` exothermic
    B
    `+"33.3 kJ mol"^(-1),` endothermic
    C
    `-"33.3 kJ mol"^(-1)`, exothermic
    D
    `+"824.2 kJ mol"^(-1),` endothermic
  • Similar Questions

    Explore conceptually related problems

    Coke does not cause reduction of Al_(2)O_(3) . Explain Delta G^(@) (in kJ mol^(-1) ) for Al_(2)O_(3) : -1582, CO = - 137.2.

    Calculate equilibrium constant for the reaction: 2SO_(2)(g) +O_(2)(g) hArr 2SO_(3)(g) at 25^(@)C Given: Delta_(f)G^(Theta) SO_(3)(g) = - 371.1 kJ mol^(-1) , Delta_(f)G^(Theta)SO_(2)(g) =- 300.2 kJ mol^(-1) and R = 8.31 J K^(-1) mol^(-1)

    The combustion of 1 mol of benzene takes place at 298 K and 1 atm . After combustion, CO_(2)(g) and H_(2)O(l) are produced and 3267.0 kJ of heat is librated. Calculate the standard entalpy of formation, Delta_(f)H^(Θ) of benzene Given: Delta_(f)H^(Θ)CO_(2)(g) = -393.5 kJ mol^(-1) Delta_(f)H^(Θ)H_(2)O(l) = -285.83 kJ mol^(-1) .

    The combustion of 1 mol of benzene takes place at 298 K. After combustion CO_(2) and H_(2)O are formed and 3267 kJ mol^(-1) of heat is liberated. Calculate Delta_(f) H^(0) (C_(6)H_(6)) . Given: Delta_(f) H^(0) (CO_(2)) = -286kJ mol^(-1), Delta_(f) H^(0) (H_(2)O) = - 393 kJ mol^(-1)

    Calculate Delta_(r)G^(c-) of the reaction : Ag^(o+)(aq)+Cl^(c-)(aq) rarr AgCl(s) Given :Delta_(f)G^(c-)._(AgCl)=-109kJ mol ^(-1) Delta_(f)G^(c-)_((Cl^(c-)))=-129k J mol ^(-1) Delta_(f)G^(c-)._((Ag^(o+)))=-77 kJ mol ^(-1)