An electronic transition in hydrogen atom resulta in the formation of `H_2` line of hydrogen in Lynn series the energies associated with the electron in each of the electron in each of the orbits involved the transition ( in kcal `mol^(-1)`) are

Options

A. `-313.6,-34.84`
B. `-313.6,-78.4`
C. `-78.4,-34.84`
D. `-78.4,-19.6`

Answer

b

Explanation

Energy of an electron in `n^(th)` orbit is given by,
`E_n=2.172xx10^(-18)xx[(Z^(2))/(n^(2))] J ` `"atom"^(-1)`
`=-1311.8xx[(z^(2))/(n^(2))]KJ mol^(-1)therfore 1 kcal=4.184 KJ)`
For hydrogen atom , atomic number,Z=1
For Lyman series,`n_1=1` and `n_2=2`
`therefore` Energy of electron in `n_1` orbit`=-313.52[(1^(2))/(1^(2))]`
-`313.52` Kcal `mol^(-1)`
`=-313.6` Kcal `mol^(-1)`
` therefore` Energy of electron in `n_2` oprbit `=313.52=[(1^(2))/(1^(2))]`
`=-78.38` Kcal `mol^(-1)`