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Among the first lines of Lyman,Balmer, p...

Among the first lines of Lyman,Balmer, paschen and Brackett series in hydrogen atomic spectra,which has the highest energy?

A

Lyman

B

Balmer

C

Paschen

D

Brackett

Text Solution

Verified by Experts

The correct Answer is:
a
Lyman series has highest energy because it appear in the UV region.
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Knowledge Check

  • In ruthorford's -164KJ, mol^(-1) -ray scattering expirement, the alpha Bracket series in hydrogen atomic spectra, which has the highest energy?

    A
    Carbon black
    B
    BalPlatinium blacker
    C
    Zinc sulphide
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    Polytetrafluoro ethylene

  • The only e^- in the H-atom resides under ordinary conditions on the first orbit when energy is supplied, the e^- moves to higher energy shells depending upon the amount of energy absorbed. When an e emits energy i.e., the e^- returns to the lowest energy state, from this Lyman, Balmer, Paschen, Bracket, Pfund series are there, so different spectral lines in the spectra of atoms correspond to different transitions of e^- s from higher to lower energy levels: In an hydrogen atom which of the following transition should be associated with highest absorption of energy

    A
    n = 1 to n = 4
    B
    n = 2 to n = 3
    C
    n = 4 to n = 1
    D
    n = 3 to n = 2

  • The only e^- in the H-atom resides under ordinary conditions on the first orbit when energy is supplied, the e^- moves to higher energy shells depending upon the amount of energy absorbed. When an e emits energy i.e., the e^- returns to the lowest energy state, from this Lyman, Balmer, Paschen, Bracket, Pfund series are there, so different spectral lines in the spectra of atoms correspond to different transitions of e^- s from higher to lower energy levels: If the shortest wavelength of H atom in Lyinan series x, then longest wavelength in Balmer series of He^+ is

    A
    `(36x)/(5)`
    B
    `(x)/(4)`
    C
    `(9x)/(5)`
    D
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