Home
Class 11
MATHS
The sum 1+3+7+15+31+...to100 terms is 2^...

The sum `1+3+7+15+31+...to100` terms is `2^(100)-102 b` b. `2^(99)-101` c. `2^(101)-102` d. none of these

Answer

Step by step text solution for The sum 1+3+7+15+31+...to100 terms is 2^(100)-102 b b. 2^(99)-101 c. 2^(101)-102 d. none of these by MATHS experts to help you in doubts & scoring excellent marks in Class 11 exams.

Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

The largest term common to the sequences 1,11,21,31,... to 100 terms and 31,36,41,46,... to 100 terms is 381 b.471 c.281 d.none of these

The HCF of 100 and 101 is 10100 (b) 1001 (c) 10101 (d) None of these

Knowledge Check

  • The number of terms in (1+x)^(101) (1+x^(2)-x)^(100) is

    A
    101
    B
    202
    C
    301
    D
    302

    • Similar Questions

    Explore conceptually related problems

    2-2+2-2+.101backslash terms=?-2(b)0 (c) 2 (d) None of these

    The number of terms common between the series 1+2+4+8+...... to 100 terms and 1+4+7+10+....... to 100 terms is a.6b.4 c.5 d.none of these

    (11.6-:0.8)(13.5-:2)=?( a) 98(b)99(c)100(d) None of these

    The number of terms in the expansion (x^2+ 1/x^2+2)^100 is (A) 3200 (B) ^102C_2 (C) 201 (D) none of these

    If t_r=2^(r/3)+2^(-r/3), then sum_(r=1)^100 t_r^3 -3 sum_(r=1)^100t_r+1= (A) (2^101+1)/2^100 (B) (2^101-1)/2^100 (C) (2^201+1)/2^100 (D) none of these

    The number of terms in te expansion of (1+5x+10x^2+10x^3+x^5)^20 is (A) 100 (B) 101 (C) 120 (D) none of these

    (2^(100))/(101) find Remainder.

    Home
    Profile