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The instantaneous current in an AC circu...

The instantaneous current in an AC circuit is l = `sqrt 2`sin(50 t + `pi` / 4 ) . The rms value of current is

A

`sqrt 2`A

B

50 A

C

90 A

D

1A

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The correct Answer is:
To find the root mean square (rms) value of the instantaneous current given by the equation \( i = \sqrt{2} \sin(50t + \frac{\pi}{4}) \), we can follow these steps: ### Step 1: Identify the Peak Current The given equation for the instantaneous current is: \[ i = \sqrt{2} \sin(50t + \frac{\pi}{4}) \] In this equation, the term \(\sqrt{2}\) represents the peak current, denoted as \(I_0\). ### Step 2: Use the Formula for RMS Value The rms value of an alternating current is given by the formula: \[ I_{\text{rms}} = \frac{I_0}{\sqrt{2}} \] where \(I_0\) is the peak current. ### Step 3: Substitute the Peak Current into the RMS Formula From Step 1, we have \(I_0 = \sqrt{2}\). Now we can substitute this value into the rms formula: \[ I_{\text{rms}} = \frac{\sqrt{2}}{\sqrt{2}} \] ### Step 4: Simplify the Expression Now, simplify the expression: \[ I_{\text{rms}} = 1 \] ### Conclusion Thus, the rms value of the current is: \[ I_{\text{rms}} = 1 \text{ A} \] ### Final Answer The rms value of the current is \(1 \text{ A}\). ---

To find the root mean square (rms) value of the instantaneous current given by the equation \( i = \sqrt{2} \sin(50t + \frac{\pi}{4}) \), we can follow these steps: ### Step 1: Identify the Peak Current The given equation for the instantaneous current is: \[ i = \sqrt{2} \sin(50t + \frac{\pi}{4}) \] In this equation, the term \(\sqrt{2}\) represents the peak current, denoted as \(I_0\). ...
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Knowledge Check

  • If the instantaneous current in a circuit is given by I = 20 cos (omega t + phi) A , the rms value of the current is

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