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In Young's double slit experiment, wavel...

In Young's double slit experiment, wavelength `lambda=5000Å` the distance between, the slits is `0.2mm` and the screen is at 200cm from the slits. The central maximum is at `x=0` The third maximum (Taking the central maximum as zeroth maximum) will be at x equal to

A

`1.67 cm`

B

`1.5 cm`

C

`0.5 cm`

D

`5.0 cm`

Text Solution

Verified by Experts

The correct Answer is:
B
Position of third maxima
`x_(3)=(3lambdaD)/d=(3(5xx10^(-5))(200))/(0.02) cm=1.5 cm`
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Knowledge Check

  • The Young's double slit experiment is carried out with light of wavelength 5000Å . The distance between the slits is 0.2 mm and the screen is at 200 cm from the slits. The central maximum is at y=0 . The third maximum will be at y equal to

    A
    `1.67 cm`
    B
    `1.5 cm`
    C
    `0.5 cm`
    D
    `5.0 cm`

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    A
    5.0 cm
    B
    0.5 cm
    C
    4.67 cm
    D
    1.5 cm

  • In Young's double slit experiment carried out with light of wavelength lamda= 5000 Å, the distance between the slits is 0.2 mm and screen is 2.0 m away from the slits. The central maximum is at n=0. the third maximum will be formed at a distance x (from the central maxima) equal to

    A
    0.5 cm
    B
    1.67 cm
    C
    1.5 cm
    D
    5 cm

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