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In Young's double slit experiment, wavel...

In Young's double slit experiment, wavelength `lambda=5000Å` the distance between, the slits is `0.2mm` and the screen is at 200cm from the slits. The central maximum is at `x=0` The third maximum (Taking the central maximum as zeroth maximum) will be at x equal to

A

`1.67 cm`

B

`1.5 cm`

C

`0.5 cm`

D

`5.0 cm`

Text Solution

Verified by Experts

The correct Answer is:
B
Position of third maxima
`x_(3)=(3lambdaD)/d=(3(5xx10^(-5))(200))/(0.02) cm=1.5 cm`
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